A bullet is fired horizontally at a height of 2 meters at a velocity of 930 m/s. Assume no air resistance. How far did the bulle
2 answers:
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Answer:
13 m/s east
Explanation:
We can solve the problem by using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision:
where
m = 0.1 kg is the mass of each puck
u1 = +13 m/s is the initial velocity of puck 1
u2 = -18 m/s is the initial velocity of puck 2 (here I assume the west direction to be the negative direction, so I put a negative sign)
v1 = -18 m/s is the final velocity of puck 1
v2 = ? is the final velocity of puck 2
Simplifying m from the formula and substituting the data, we can find the final velocity of puck 2, v2:
And the positive sign means that puck 2 is moving east.
Answer: 1.9 m/s
Explanation:
1) Data:
height, y = 0
range, x = 0.77m
angle, α = 45°
question, horizontal velocity, Vox = ?
2) Physical principles and formulas
Projectile motion.
3) Solution
Factor
Discard t = 0 and solve for the other factor:
Find Vx:
Vx = 1.9m/s ← answer