Answer:
The other angle is 75⁰
Explanation:
Given;
velocity of the projectile, v = 10 m/s
range of the projectile, R = 5.1 m
angle of projection, 15⁰
The range of a projectile is given as;

To find another angle of projection to give the same range;

<u>Check: </u>
sin(2θ) = sin(2 x 75) = sin(150) = 0.5
sin(2θ) = sin(2 x 15) = sin(30) = 0.5
<span>The answer to your question would be:
3. The same</span>
Answer:
the liquid has less height than the mercury
h_{ liquid} = 
Explanation:
The pressure as a function of the height is given by
P = ρ g h
where ρ is the density of the liquid, g the acceleration of gravity and h the height reached by the column of the liquid
In that case they say that the pressure is the standard one that is P = 1.01 10⁵ Pa = 760 mmHg
The first way to give the pressure is in SI units and the second way is the height that the mercury column reaches
In the case of building a barometer with a liquid that has a density greater than that of mercury
ρ_liquid > ρ_Hg
the pressure
P =ρ_lquid g h_liquid
if we have the same pressure
ρ_{Hg} g h_{Hg} = ρ_{liquid} g h_{liquid}
h_{ liquid} =
therefore the liquid has less height than the mercury
Answer:
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