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Annette [7]
2 years ago
9

Lolliguncula brevis squid use a form of jet propulsion to swim—they eject water out of jets that can point in different directio

ns, allowing them to change direction quickly. When swimming at a speed of 0.15m/s0.15m/s or greater, they can accelerate at 1.2m/s21.2m/s 2 .
(a) Determine the time interval needed for a squid to increase its speed from 0.15m/s0.15m/s to 0.45m/s0.45m/s.
(b) What other questions can you answer using the data?
Physics
1 answer:
romanna [79]2 years ago
6 0

Answer:

a) t = 0.25 s,  b)  x = 0.075 m

Explanation:

a) For this exercise we will use kinematic relationships in one dimension

         v = v₀ + a t

in the problem they indicate the initial velocity v₀ = 0.15 m / s, the final velocity v = 0.45 m / s and the acceleration of the squid a = 1.2 m / s²

          t = \frac{v -v_o}{a}

       

we calculate

         t = \frac{0.45 - 0.15}{1.2}

         t = 0.25 s

b) We can also find the distance traveled during this acceleration

         v² = v₀² + 2a x

         x = \frac{v^2 -v_o^2 }{2a}

let's calculate

         x = \frac{0.45^2 - 0.15^2 }{2 \  1.2}

         x = 0.075 m

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kirill115 [55]

Answer:

B. The atom gains 1 electron, to make a total of 18 electrons.

Explanation:

Chlorine is the 17th element in the periodic table, so it has atomic number 17:

Z = 17

This means that a neutral atom of chlorine has 17 protons and 17 electrons.

When a chlorine atom gains 1 electron, its electric charge (initially zero) becomes -1, since the electron has negative charge of -1 (in elemntary charge units). This also means that the number of electrons in the ion is now

17 + 1 = 18

So the correct answer is

B. The atom gains 1 electron, to make a total of 18 electrons

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baherus [9]

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On the surface of the earth the weight of an object is 200 lb. Determine the height of the
siniylev [52]

Answer:

The height of the  object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

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200=\dfrac{Gmm_{e}}{(3958.756)^2}

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Put the value into the formula

125=\dfrac{200\times(3958.756)^2}{r^2}

r^2=\dfrac{200\times(3958.756)^2}{125}

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r=5007.4\ miles

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Data given:

Fh=400N

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