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Yuki888 [10]
3 years ago
14

In part B of the lab, when the current flows through the orange part of the wire from right to left, the wire deflects (or moves

) ____. This is in accordance with the right-hand-rule.
Physics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

This seems to be incomplete, as we do not have any information about the magnetic field surrounding the wire, but we can answer in a general way.

We know that for a wire of length L, with a current I, and in a magnetic field B, the force can be written as:

F = L*(IxB)

if we define the right as the positive x-axis, and knowing that the current flows to the right, we can write:

I = i*(1, 0, 0)

And the field will be some random vector that can't be parallel to the current because in that case, we do not have any force.

To find the direction of the force, which will tell us the direction in which the wire deflects or moves, first, we need to point with our thumb in the direction of the current, in this case, to the right.

Now, with the hand open, using the tip of our other fingers we point in the direction of the magnetic field.

For example, if the magnetic field is in the positive z-axis, we will point upwards.

Now the palm of our hand tells us in which direction the force is applied.

This is the right-hand rule.

For example, in the case that the current goes to the right and the magnetic field is upwards, we could see that the force is to the front.

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During a plane showcase, a pilot makes circular "looping" with a speed equal to the sound speed (340 m/s). However, the pilot ca
Dmitriy789 [7]

Answer:

1472.98 m

Explanation:

Data provided:

Speed of circular looping, v = 340 m/s

Acceleration, a = 8g

here,

g is the acceleration due to the gravity = 9.81 m/s²

Now,

the centripetal acceleration is given as,

a=\frac{v^2}{r}

r is the radius of the loop

on substituting the respective values, we get

8\times9.81=\frac{340^2}{r}

or

r = 1472.98 m

5 0
3 years ago
50 points: can someone help me with this question please: A classroom is 5.345m long, 4.128m wide, and 3.859m high. What is the
lesya [120]

this is basically the same as volume, no?

So, 5.345*4.128*3.859=85.145

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3 years ago
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mixas84 [53]
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HURRY URGENT ASAP I WILL GIVE BRAINLIEST
Leto [7]

Answer:

A

Explanation:

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3 years ago
Curtis, a student in our class, makes the following statement: The puck reached a slightly higher location on the ramp than I pr
Sindrei [870]

Answer and Explanation: No, the explanation is not plausible. The puck sliding on the ice is an example of the <u>Principle</u> <u>of</u> <u>Conservation</u> <u>of</u> <u>Energy</u>, which can be enunciated as "total energy of a system is constant. It can be changed or transferred but the total is always the same".

When a player hit the pluck, it starts to move, gaining kinetic energy (K). As it goes up a ramp, kinetic energy decreases and potential energy (P) increases until it reaches its maximum. When potential energy is maximum, kinetic energy is zero and vice-versa.

So, at the beginning of the movement the puck only has kinetic energy. At the end, it gains potential energy until its maximum.

The representation is as followed:

K_{i}+P_{i}=K_{f}+P_{f}

K_{i}+0=0+P_{f}

\frac{1}{2}mv^{2} = mgh

As we noticed, mass of the object can be cancelled from the equation, making height be:

h=\frac{v^{2}}{2g}

So, the height the puck reaches depends on velocity and acceleration due to gravity, not mass of the puck.

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3 years ago
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