Using the conservation of momentum,
ma*va1 + mb*vb1 = ma*va2 + mb*vb2
Let:
ma = mass of the ball
va = velocity of the ball
mb = mass of the man
vb = velocity of the man
The subscript 1 is known as initials while 2 is for finals.
Before the man throws the ball, he starts at rest, meaning the initial velocity of the ball and the initial velocity of the man are zero. So
0 = ma*va2 + mb*vb2
Given ma = 10 kg; va = 20 m/s; mb = 90 kg; vb is unknown, therefore
-(mb*vb2) = ma*va2
vb2 = -(ma*va2)/mb2 = -(10*20)/90 = -2.22 m/s
Notice that his velocity is negative because when he finally throws the ball (say to the right), he moves at the opposite direction (that is to the left) on which he stands on the frictionless surface.
Answer:
3
Explanation:
it's too because on you measuring mass of something
Answer:
Explanation:
Required
The units of A and B
From the question, we understand that:
This implies that each of and will have the same unit as
So, we have:
The unit of t is (s); So, the expression becomes
Divide both sides by
Answer:
Every 2.2 kg is 1 pound. So mulitply 19 * 2.2. It's gonna be equal to 41.8
Explanation: