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bonufazy [111]
3 years ago
9

An ion has unequal numbers of which two particles?

Physics
1 answer:
Scrat [10]3 years ago
7 0
Protons and electrons
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My Fitness Goals: (List your specific and general goals)
Leokris [45]
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3 0
3 years ago
How many does it cost the food in coast
sineoko [7]
Attaché something else so we can see what you're talking abojt
7 0
3 years ago
A 0.5 kg block is attached to a spring (k = 12.5 N/m). The damped frequency is 0.2% lower than the natural frequency, (a) What i
Tju [1.3M]

Answer:

a)  1.58 kg s^{-1}

b)  x_m e^{-1.58t}   x_m is initial amplitude

c) 5 kg s^{-1}

Explanation:

given data:

mass =0.5 kg

k = 12.5 N/m

from the data given

a) w_d = w_o - \frac{0.2}{100}w_o

= w_o - 0.002w_o = 0.99w_o

w_d = \sqrt{\frac{k}{m} - \frac{b^2}{4m^2}

0.998w_o = \sqrt{w_o^2 - \frac{b^2}{4m^2}

(0.998w_o)^2 = w_o^2 -\frac{b^2}{1}

b^2 = w_o^2 -(0.998w_o)^2

b^2 = w_o^2(1-0.998^2) = 3.996 *10^{-3} w_o^2

b = w_o\sqrt{3.996*10^{-3}}

b = \frac{12.5}{0.5}\sqrt{3.996*10^{-3}} = 1.58 kg s^{-1}

b)x = x_m e^{\frac{-bt}{2m}}

   x = x_m e^{-1.58t}{1} = x_m e^{-1.58t}    where x_m is initial amplitude

c) critical damping amplitude

c_c =2\sqrt{km} = 2\sqrt{12.5*.5} = 5 kg s^{-1}

5 0
3 years ago
The terrestrial planets are made almost entirely of elements heavier than hydrogen and helium. According to modern science, wher
drek231 [11]

Hydrogen makes stars and stars spend most of their lifetime making helium.

The heavier elements are made when an old-age, high mass star explodes as a nova or supernova and then dies.

4 0
4 years ago
Read 2 more answers
(a) What is the escape speed on a spherical asteroid whose radius is 500. km and whose gravitational acceleration at the surface
navik [9.2K]

Answer:

a) v= 1732.05m/s

b) d=250000m

c) v= 1414.214m/s

Explanation:

Notation

M= mass of the asteroid

m= mass of the particle moving upward

R= radius

v= escape speed

G= Universal constant

h= distance above the the surface

Part a

For this part we can use the principle of conservation of energy. for the begin the initial potential energy for the asteroid would be U_i =-\frac{GMm}{R}.

The initial kinetic energy would be \frac{1}{2}mv^2. The assumption here is that the particle escapes only if is infinetely far from the asteroid. And other assumption required is that the final potential and kinetic energy are both zero. Applying these we have:

-\frac{GMm}{R}+\frac{1}{2}mv^2=0   (1)

Dividing both sides by m and replacing \frac{GM}{R} by a_g R

And the equation (1) becomes:

-a_g R+\frac{1}{2} v^2=0   (2)

If we solve for v we got this:

v=\sqrt{2 a_g R}=\sqrt{2x3\frac{m}{s^2}x500000m}=1732.05m/s

Part b

When we consider a particule at this surface at the starting point we have that:

U_i=-\frac{GMm}{R}

K_i=\frac{1}{2}mv^2

Considering that the particle is at a distance h above the surface and then stops we have that:

U_f=-\frac{GMm}{R+h}

K_f=0

And the balance of energy would be:

-\frac{GMm}{R}+\frac{1}{2}mv^2 =-\frac{GMm}{R+h}

Dividing again both sides by m and replacing \frac{GM}{R} by a_g R^2 we got:

-a_g R+\frac{1}{2}v^2 =-\frac{a_g R^2}{R+h}

If we solve for h we can follow the following steps:

R+h=-\frac{a_g R^2}{-a_g R+\frac{1}{2}v^2}

And subtracting R on both sides and multiplying by 2 in the fraction part and reordering terms:

h=\frac{2a_g R^2}{2a_g R-v^2}-R

Replacing:

h=\frac{2x3\frac{m}{s^2}(500000m)^2}{2(3\frac{m}{s^2})(500000m)-(1000m/s)^2}- 500000m=250000m

Part c

For this part we assume that the particle is a distance h above the surface at the begin and start with 0 velocity so then:

U_i=-\frac{GMm}{R+h}

K_i=0

And after the particle reach the asteroid we have this:

U_f=-\frac{GMm}{R}

K_f=\frac{1}{2}mv^2

So the balance of energy would be:

-\frac{GMm}{R+h}=-\frac{GMm}{R}+\frac{1}{2}mv^2

Replacing again a_g R^2 instead of GM and dividing both sides by m we have:

-\frac{a_g R^2}{R+h}=-a_g R+\frac{1}{2}v^2

And solving for v:

a_g R-\frac{a_g R^2}{R+h}=\frac{1}{2}v^2

Multiplying both sides by two and taking square root:

v=\sqrt{2a_g R-\frac{2a_g R^2}{R+h}}

Replacing

v=\sqrt{2(3\frac{m}{s^2})(500000m)-\frac{2(3\frac{m}{s^2}(500000m)^2}{500000+1000000m}}=1414.214m/s

3 0
3 years ago
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