Answer:
The principal elements are Iron, Nickel, Chromium
It has 0.37% to 0.43% Carbon
It is hardenable.
It can be hardened by cold working, annealing, quenching.
Explanation:
A)
The chemical composition of AISI 4340 Steel are as follows:
Iron --- 95% to 96%
Nickel --- 1.6% to 2.0%
Chromium --- 0.7% to 0.9%
Manganese --- 0.6% to 0.8%
Carbon --- 0.37% to 0.43%
Molybdenum --- 0.2% to 0.3%
Silicon --- 0.15% to 0.30%
Sulfur --- 0.040%
Phosphorous --- 0.0350%
So, the principal alloy elements from this composition are <u>Iron, Nickel and Chromium</u>
B)
The carbon content in this alloy is <u>0.37% to 0.43%</u>
C)
<u>Yes, it can be hardened</u>.
D)
<u>It can be Hardened by Cold Working, Annealing or Quenching</u>.
Answer:
A) 0 °C, because it is the melting point of ice.
Explanation:
- Point B is the temperature at which the water is converted from ice (solid phase) to liquid water (liquid phase), which is the melting transition of water.
Melting point of the water is at 0.0°C.
<em>So, the right choice is: A) 0 °C, because it is the melting point of ice. </em>
<em></em>
Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!
Reactants on the left and products on the right
Explanation:
the physical and chemical properties of an element are periodic functions of their atomic number.
