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2 years ago

44 mL of H2CrO4 is needed to neutralize 176mL of a 10M solution of Pd(OH)4. What is the molarity of this solution?

Chemistry

1 answer:

balandron [24]2 years ago

3 0

Answer: The molarity of this solution is 2.5 M.

Explanation:

Given : $V_1 = 44 mL$ , $V_2 = 176 mL$

$M_1 = 10 M$

Therefore, the value of molarity of the solution is calculated using following formula.

$M_1 \times V_1 = M_2 \times V_2$

Substitute the values into above formula as follows.

$M_1 \times V_1 = M_2 \times V_2\\10 M \times 44 mL = M_2 \times 176 mL\\M_2 = \frac{10 M \times 44 mL}{176 mL}\\= 2.5 M$

Hence, molarity of the solution is 2.5 M.

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A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0- L vessel at 300 K . The following equilibr

umka2103 [35]

Answer:

The concentration of N2 at the equilibrium will be 0.019 M

Explanation:

Step 1: Data given

Number of moles of NO = 0.10 mol

Number of moles of H2 = 0.050 mol

Number of moles of H2O = 0.10 mol

Volume = 1.0 L

Temperature = 300K

At equilibrium [NO]=0.062M

Step 2: The balanced equation

2NO(g) + 2H2(g) → N2(g) + 2H2O(g)

Step 3: Calculate the initial concentration

Concentration = Moles / volume

[NO] = 0.10 mol / 1L = 0.10 M

[H2] = 0.050 mol / 1L = 0.050 M

[H2O] = 0.10 mol / 1L = 0.10 M

[N2] = 0 M

Step 4: Calculate the concentration at the equilibrium

[NO] at the equilibrium is 0.062 M

This means there reacted 0.038 mol (0.038M) of NO

For 2 moles NO we need 2 moles of H2 to produce 1 mol N2 and 2 moles of H2O

This means there will also react 0.038 mol of H2

The concentration at the equilibrium is 0.050 - 0.038 = 0.012 M

There will be porduced 0.038 moles of H2O, this means the final concentration pf H2O at the equilibrium is 0.100 + 0.038 = 0.138 M

There will be produced 0.038/2 = 0.019 moles of N2

The concentration of N2 at the equilibrium will be 0.019 M

5 0

3 years ago

What is science? Why do you think science is important?

ryzh [129]

Answer:

Science is the study of the physical or material world. Science is important because it can answer questions about new ideas and can advance technologies

Explanation:

3 0

4 years ago

Which statement below about contrasting Hb and Mb is FALSE?

olchik [2.2K]

Answer:

C. Hb binds O2 more tightly than Mb.

Explanation:

Hb and Mb are both oxygen carrier protiens which contain the heme group. Hb has 4 heme units in 1 moleucle which work via coperative effect. On the other hand, Mb has only one heme unit.

From above theory, statement A and B are correct.

Although the heme group of the Mb is identical to those of Hb, Mb has a higher affinity for carrying oxygen than hemoglobin.

Hence, Statement C is wrong.

Thats why the function of hemoglobin is to transport oxygen and that of myoglobin is to store oxygen.

When a curve is plotted between oxygen accepted and the pressure of the oxygen, Hb shows sigmoidal, whereas Mb shows hyperbolic oxygen saturation curves. The statement D is correct.

Bohr effect and various factors decribe the statement : Hb-oxygen binding is dependent on physiological changes in pH, whereas Mb-oxygen binding is not. The statement E is also correct.

7 0

3 years ago

How many grams of H 2O are produced from 28.8 g of O 2? (Molar Mass of H 2O = 18.02 g) (Molar Mass of O 2=32.00 g) 4 NH 3 (g) +

krek1111 [17]

Answer: 13.9 g of $H_2O$ will be produced from the given mass of oxygen

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles$

The balanced chemical reaction is:

$4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)$

According to stoichiometry :

7 moles of $O_2$ produce = 6 moles of $H_2O$

Thus 0.900 moles of $O_2$ will produce = $\frac{6}{7}\times 0.900=0.771moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=0.771moles\times 18.02g/mol=13.9g$

Thus 13.9 g of $H_2O$ will be produced from the given mass of oxygen

5 0

3 years ago

Stoichiometric calculations are based on balanced chemical equations. the reason that chemical equations must always be balanced

Roman55 [17]

Answer: Chemical equations are balanced in order to: 1) satisfy the Law of Conservation of Mass, and 2) establish the mole relationships needed for stoichiometric calculations. The Law of Conservation of Mass: The Law of Conservation of Mass states that mass cannot be created or destroyed.

6 0

4 years ago