The first thing to do is to calculate the new concentration of the solution after dilution. We do as follows:
M1V1 = M2V2
(3.0 M).006 L = M2 (18 L)
M2 = 0.001 M HNO3
When in solution it dissociated into ions as follows:
HNO3 = H+ + NO3-
[H+] = 0.001 M HNO3 ( 1 mol H+ / 1 mol HNO3 ) = 0.001 M H+
pH = -log[H+] = -log 0.001 = 3
Answer:
4.45 atm
Explanation:
Applying,
PV = P'V'............ Equation 1
Where P = Initial pressure of the container, V = Initial volume of the container, P' = Final pressure of the container, V' = Final volume of the container.
make P the subject of the equation
P = P'V'/V........... Equation 2
From the question,
Given: V = 55.2 L, P' = 8.53 atm, V' = 28.8 L
Substitute these values into equation 2
P = (8.53×28.8)/55.2
P = 4.45 atm
Answer:
Explanation:
Look at the reaction.
2NH3 ===> N2 + 3H2
It's a molecule that is breaking down to two elements on the periodic table. We used to call such a thing as a simple decomposition.
