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inessss [21]
3 years ago
9

PLS HELP SOON I GUESS

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

the answer is -2 if you look at the left side of the graph and were the line is at you will see that the number goes through -2.

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(3Q) Find the amplitude and period of f(t)= -tan.0t
Vanyuwa [196]

Answer:

It has no amplitud and the period is 5pi/2

Step-by-step explanation:

Given a function of the following type:

f(t) = AtanB(t + C)

The function has no amplitud, given that it doesn't have maximum or minimum value.  And the period is given by: pi/B

In this case, we have f(t)= -tan0.4t. Then:

B = 0.4

⇒ Period = pi/0.4 = 5pi/2

Therefore, the answer is: It has no amplitud and the period is 5pi/2

8 0
3 years ago
ILL DO BRAINLIEST
Luden [163]

Answer:

a. X=6°

b. 6(6)-8= 28°

c. 28+( 5(6)-2) = 56°

4 0
2 years ago
Please help me <br>ineed it now ​
yanalaym [24]

Answer:

look at explanation

Step-by-step explanation:

To solve all of these questions you just need to scale. While scaling you can divide or multiply.

1. \frac{180 km}{4 hrs} (divide by 4 to get unit rate)

     unit rate = \frac{45km}{1hr}

2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know \frac{40 miles}{1 hr}, the answer is...

"It'll only take one hour to travel 40 miles. This is correct because the unit rate is \frac{40 miles}{1 hr}. "

3. Knowing that the constant speed of the plane is \frac{800 km}{1 hour\\}, we can scale then add half of the unit rate to get our answer.

\frac{800 km}{1 hour\\} x 3 = \frac{2400 km}{3 hrs}   800 x 3 = 2400

then add half of unit rate which is \frac{400 km}{30 mins}  \sqrt[2]{800} = 400

so, our answer is \frac{2800 km}{3.5 hours}

4.  \frac{3km}{30 mins} <--- ( divided by 2) \frac{6 km}{1 hr} ( multiplied x 2.5) ---> \frac{15 km}{2.5 hrs}

To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.

Elmer would take 2 and a half hours to ride 15 km.

5. The boys speed is \frac{4 km}{1 hr}. All we need to do is divide by 2. \sqrt[2]{8} = 4

3 0
3 years ago
Find the surface area! Please I need it quick
zloy xaker [14]

Step-by-step explanation:

<h2>We first find the area of a trapezium and rectangular face</h2><h2>Fourmula to find the are of a trapezium is:</h2><h3>Area=1/2*(B+b)*h</h3><h3> =1/2*3.7*1.9</h3><h3> =3.515m²</h3><h2 /><h2>Since every rectangular face is different we gotta find each of them</h2>

<h3>Area1=4.8*2.1</h3><h3> =10.08 m²</h3><h3>Area2=4.8*1.4=6.72m²</h3><h3>Area3=4.8*2.3=11.05m²</h3><h3>Area4=4.8*1.9=9.12m²</h3>

<h3 /><h3>Now we find the area of the whole prism</h3><h3>Area=3.515*2+10.08+6.72+11.05+9.12</h3><h3>Area=44m²</h3>

<h2>Sorry my wireless went down!!!</h2><h2>Hope this helps and you already know what I would like to get</h2>

7 0
3 years ago
Please help! Correct answer only, please! Consider the following information matrices for the price of clothing at a clothing st
ololo11 [35]

Answer: b) Large blue t-shirt & Medium RC jeans

<u>Step-by-step explanation:</u>

The subscript numbers attached to the matrix letter represents the:

ROW, COLUMN

A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\

A₁,₃ = 1st row, 3rd column

         1st row is Blue, 3rd column is Large

B₃,₂ = 3rd row, 2nd column

         3rd row is RC jeans, 2nd column is Medium

A₁,₃ + B₃,₂ = Large blue t-shirt & Medium RC jeans

8 0
3 years ago
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