Answer:
It has no amplitud and the period is 5pi/2
Step-by-step explanation:
Given a function of the following type:
f(t) = AtanB(t + C)
The function has no amplitud, given that it doesn't have maximum or minimum value. And the period is given by: pi/B
In this case, we have f(t)= -tan0.4t. Then:
B = 0.4
⇒ Period = pi/0.4 = 5pi/2
Therefore, the answer is: It has no amplitud and the period is 5pi/2
Answer:
look at explanation
Step-by-step explanation:
To solve all of these questions you just need to scale. While scaling you can divide or multiply.
1.
(divide by 4 to get unit rate)
unit rate = 
2. If it takes one hour to travel 40 miles, then we don't have to scale or anything. We know
, the answer is...
"It'll only take one hour to travel 40 miles. This is correct because the unit rate is
. "
3. Knowing that the constant speed of the plane is
, we can scale then add half of the unit rate to get our answer.
x 3 =
800 x 3 = 2400
then add half of unit rate which is
= 400
so, our answer is 
4.
<--- ( divided by 2)
( multiplied x 2.5) ---> 
To get an easier way to find the answer, if possible you can scale back farther than the 1 hour mark.
Elmer would take 2 and a half hours to ride 15 km.
5. The boys speed is
. All we need to do is divide by 2.
= 4
Step-by-step explanation:
<h2>We first find the area of a trapezium and rectangular face</h2><h2>Fourmula to find the are of a trapezium is:</h2><h3>Area=1/2*(B+b)*h</h3><h3> =1/2*3.7*1.9</h3><h3> =3.515m²</h3><h2 /><h2>Since every rectangular face is different we gotta find each of them</h2>
<h3>Area1=4.8*2.1</h3><h3> =10.08 m²</h3><h3>Area2=4.8*1.4=6.72m²</h3><h3>Area3=4.8*2.3=11.05m²</h3><h3>Area4=4.8*1.9=9.12m²</h3>
<h3 /><h3>Now we find the area of the whole prism</h3><h3>Area=3.515*2+10.08+6.72+11.05+9.12</h3><h3>Area=44m²</h3>
<h2>Sorry my wireless went down!!!</h2><h2>Hope this helps and you already know what I would like to get</h2>
Answer: b) Large blue t-shirt & Medium RC jeans
<u>Step-by-step explanation:</u>
The subscript numbers attached to the matrix letter represents the:
ROW, COLUMN
![A=\left[\begin{array}{ccc}a_{1,1}&a_{1, 2}&a_{1, 3}\\a_{2,1}&a_{2, 2}&a_{2, 3}\\a_{3,1}&a_{3, 2}&a_{3, 3}\end{array}\right] \qquad B=\left[\begin{array}{ccc}a_{1,1}&b_{1, 2}&b_{1, 3}\\b_{2,1}&b_{2, 2}&b_{2, 3}\\b_{3,1}&b_{3, 2}&b_{3, 3}\end{array}\right]\\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B1%2C1%7D%26a_%7B1%2C%202%7D%26a_%7B1%2C%203%7D%5C%5Ca_%7B2%2C1%7D%26a_%7B2%2C%202%7D%26a_%7B2%2C%203%7D%5C%5Ca_%7B3%2C1%7D%26a_%7B3%2C%202%7D%26a_%7B3%2C%203%7D%5Cend%7Barray%7D%5Cright%5D%20%5Cqquad%20B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B1%2C1%7D%26b_%7B1%2C%202%7D%26b_%7B1%2C%203%7D%5C%5Cb_%7B2%2C1%7D%26b_%7B2%2C%202%7D%26b_%7B2%2C%203%7D%5C%5Cb_%7B3%2C1%7D%26b_%7B3%2C%202%7D%26b_%7B3%2C%203%7D%5Cend%7Barray%7D%5Cright%5D%5C%5C)
A₁,₃ = 1st row, 3rd column
1st row is Blue, 3rd column is Large
B₃,₂ = 3rd row, 2nd column
3rd row is RC jeans, 2nd column is Medium
A₁,₃ + B₃,₂ = Large blue t-shirt & Medium RC jeans