1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Whitepunk [10]
2 years ago
14

If a liquor law is violate the liquor authority can issue a citation today

Chemistry
1 answer:
Basile [38]2 years ago
8 0

If a liquor law is violated, the liquor authority can issue a citation of fine. The other consequence of liquor law violation is Liquor- license suspension.

<h2>What is liquor law?</h2>

Liquor law is also called Alcohol laws. Alcohol laws are the laws which are related to the manufacture, use and the sale of alcohol or alcoholic beverages that contains ethanol. If this law is violated, the liquor authority can issue a fine as well as the suspension of Liquor- license so we can conclude that fine and Liquor- license suspension are the consequences of violation of liquor law.

Learn more about law here: brainly.com/question/820417

You might be interested in
What agent of weathering is acid precipitation?
Alona [7]
It would be considered acid rain in the sense of dew fall
3 0
2 years ago
Gold has a density of 1,200 lb./ft. What is the density of gold in g/em? For conversion factors use I lb. 453.6 g, and l inch-2.
Jlenok [28]

<u>Answer:</u> The density of gold in g/cm^3 is 19.22g/cm^3

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object. Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of gold = 1200lb/ft^3

Using conversion factors:

1 lb = 453.6 g

1 feet = 12 inches

1 inch = 2.54 cm

Converting given quantity into g/cm^3, we get:

\Rightarrow (\frac{1200lb}{ft^3})\times (\frac{453.6g}{1lb})\times (\frac{1ft}{12inch})^3\times (\frac{1inch}{2.54cm})^3\\\\\Rightarrow 19.22g/cm^3

Hence, the density of gold in g/cm^3 is 19.22g/cm^3

6 0
3 years ago
What is the scientific method 1-7?
IRINA_888 [86]
#1- Identify a problem
#2- Collect info on your problem
#3- Make a hypothesis
#4- Design an experiment to test your hypothesis
#5- Collect data and observations
#6- Accept or reject your hypothesis
#7- Record results
Hope this helps.
3 0
3 years ago
What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for meth
Ivenika [448]
The mole fraction of a product is the number of moles of the product divided by the total number of moles of the solution.

Here moles of methanol = 6.0 moles

Moles of solution = 6.0 moles of methanol + 3.0 moles of water = 9.0 moles of solution

Mole fraction of methanol = 6.0 / 9.0 = 0.67

Answer: 0.67  
4 0
2 years ago
What is the value of x in the equation below?
Colt1911 [192]
If the question includes x only than it’s value would be 1
8 0
3 years ago
Read 2 more answers
Other questions:
  • What types of waves are produced by a jackhammer?
    12·2 answers
  • Im the only noble gas with 2 electrons
    10·2 answers
  • Which of the following is not true of a pseudoscience? It is a practice or belief that claims to be science, It does not follow
    9·1 answer
  • What is a chemical off of the periodic table that is sticky
    9·2 answers
  • It takes 208.4 kJ of energy to remove 1 mole of electrons from 1 mole of atoms on the surface of rubidium metal. How much energy
    15·1 answer
  • Where are globular clusters found
    11·2 answers
  • Which of the following statements is true?
    13·2 answers
  • How many moles of gas does it take to occupy 120 L at a pressure of 233 kPa and a temperature of 340 K?
    8·2 answers
  • What occurs to the electromagnetic radiation from the sun enters earths atmosphere
    13·2 answers
  • PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!