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FrozenT [24]
3 years ago
8

Marta is standing 4 ft behind a fence 6 ft 6 in. tall. When she looks over the fence, she can just see the top edge of a buildin

g. She knows that the building is 32 ft 6 in. behind the fence. Her eyes are 5 ft from the ground. How tall is the building? Give your answer to the nearest half foot.

Physics
1 answer:
klasskru [66]3 years ago
6 0

Answer: 93ft

Explanation: Martha's eyesight make an angle with the fence, this is solved as a triangle problem.

We first convert all the dimensions to inches using the fact that 12 inches make 1 ft.

To solve for the angle

Tan § = 18/48 = 0.375

§ = tan^-1 of 0.375 = 20.55°

This same angle elevates to the edge of the building

Tan 20.55 = 399/x

x = 399/tan 20.55

x = 1040 inches

Height of building = x + height of fence

Height of building = 1040 + 78 = 1118 inches

Converting back to ft it becomes

1118/12 = 93 ft 2 inches

Approximately 93ft

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According to Archimedes’ principle, the mass of a floating object equals the mass of the fluid displaced by the object. Use this
Andrew [12]

Answer:

Part a)

\rho = 0.55 g/cm^3

Part b)

\rho_L = 1.49 g/cm^3

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

Explanation:

Part a)

As we know that when cylinder float in the water then weight of the cylinder is counter balanced by the buoyancy force

So here we know

buoyancy force is given as

F_b = \rho_w V_{sub} g

F_b = (1 g/cm^3) (30 - 13.5) Ag

F_b = 16.5 Ag

Now we know that the weight of the cylinder is given as

W = \rho (30 cm)A g

now we have

\rho (30 cm) A g = 16.5 A g

\rho = 0.55 g/cm^3

Part b)

When the same cylinder is floating in other liquid then we will have

F_b = \rho_L (30 - 18.9 )A g

so we have

\rho_L (11.1) Ag = 0.55(30) Ag

\rho_L = 1.49 g/cm^3

Part c)

Since we know that the base area will remain same always

so here the length and width of the object is not necessary to obtain the above data in such type of questions

3 0
3 years ago
The force that contributed to the formation of planets, determines the motion of bodies in the solar system, and pulls objects t
kykrilka [37]

Answer:

The force of gravity

Explanation:

Gravity was studied, by early scientists such as Copernicus and others, Galileo was the first to ensure that planets moved according to a physical equation that depended on a force that caused celestial bodies to move and interact with each other. But years later Newton based on studies conducted deciphering what Galileo assumed, he was able to find the equation of the force of gravity in any body in the universe. This equation depends on the masses of the two interacting bodies, the distance between them and a constant, which I call universal gravitation constant.

F_{g}=G*\frac{m_{1}*m_{2}}{r^2}

Fg = gravity force [N]

G =  universal gravitation constant = 6.67*10^(-11) [N*m^2/kg^2]

m1 = mass of the 1st body [kg]

m2 = mass of the 2nd body [kg]

r = distance between the bodies [meters]

6 0
3 years ago
Astronaut Rob leaves Earth in a spaceship at a speed of 0.960crelative to an observer onEarth. Rob's destination is a star syste
Slav-nsk [51]

To solve this problem we will use the mathematical definition of the light years in metric terms, from there, through the kinematic equations of motion we will find the distance traveled as a function of the speed in proportion to the elapsed time. Therefore we have to

1Ly =9.4605284*10^{15}m \rightarrow 'Ly'means  Light Year

Then

14.4Ly = 1.36231609*10^{17} m

If we have that

v= \frac{x}{t} \rightarrow t = \frac{x}{t}

Where,

v = Velocity

x = Displacement

t = Time

We have that

t = \frac{1.36231609*10^{17}}{0.96c} \rightarrow c= Speed of light

t = \frac{1.36231609*10^{17}}{0.96(3*10^8)}

t= 454105363 s (\frac{1hour}{3600s})

t= 126140 hours(\frac{1day}{24hours})

t= 5255.85 days(\frac{1 year}{365days})

t = 14.399 years

Therefore will take 14.399 years

5 0
3 years ago
Please Help Me!
balandron [24]

The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

<h3>What is image distance?</h3>

This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.

To calculate the image distance, we use the formula below.

Formula:

  • 1/f = 1/u+1/v........... Equation 1

Where:

  • f = Focal length of the mirror
  • v = Image distance
  • u = object distance

From the question,

Given:

  • f = 0.45 m
  • u = 0.25 m

Substitute these values into equation 1 and solve for the image distance

  • 1/0.45 = 1/0.25 + 1/v
  • 2.22 = 4+1/v
  • 1/v = 2.22-4
  • 1/v = -1.78
  • v = 1/(-1.78)
  • v = -0.56 m

Hence, The image distance is -0.56 m.

Learn more about image distance here: brainly.com/question/17273444

5 0
2 years ago
Why do we not feel air pressure?
professor190 [17]

Answer:

Explanation:

Is beacuse of the air within our bodys is exerting the same pressure out wards so tjere is no pressure difference

8 0
3 years ago
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