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2 years ago

A rocket is fired at a 45° angle, what is the direction of the horizontal velocity vector at the peak height?

Physics

1 answer:

Bess [88]2 years ago

7 0

Answer:

B: Horizontally to the left

Explanation:

Horizontal velocity is always constant throughout the entire trajectory of the rocket and acts in the horizontal direction in which the rocket was launched. This is because gravity only acts in the downwards vertical direction.

So in order words at peak height, horizontal velocity is in the horizontal direction in which the rocket was launched.

So if it was to the left, then direction is left but if right, then direction is right.

Looking at the options, the most appropriate will be:

Horizontally to the left

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An object glides on a horizontal tabletop with a coefficient of kinetic friction of 0.5. If its initial velocity is 4.3 m/s, how

Shkiper50 [21]

Answer:

Time, t = 0.87 seconds

Explanation:

Given that,

Initial velocity of the object, u = 4.3 m/s

The coefficient of kinetic friction between horizontal tabletop and the object is 0.5

We need to find the time taken by the object for the object to come to rest i.e. final velocity will be 0.

Using first equation of motion to find it as :

$v=u+at$

a is the acceleration, here, $a=\mu g$

$0=u+\mu gt$

$t=\dfrac{u}{\mu g}\\\\t=\dfrac{4.3}{0.5\times 9.8}\\\\t=0.87\ s$

So, the time taken by the object to come at rest is 0.87 seconds. Hence, this is the required solution.

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2 years ago

Calculate, using a diagram, the resultant of the following vector combinations:

Veronika [31]

Add them together with south being negative. (-350 + 25) to get 325 south

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2 years ago

Two point charges, initially 2.0 cm apart, experience a 1.0 N force. If they are moved to a new separation of 0.25 cm, what is t

den301095 [7]

Explanation:

Th electric force between charges is inversely proportional to the square of distance between them. It means,

$F\propto \dfrac{1}{r^2}$

Initial distance, r₁ = 2 cm

Final distance, r₂ = 0.25 cm

Initial force, F₁ = 1 N

We need to find the electric force between charges if the new separation of 0.25 cm. So,

$\dfrac{F_1}{F_2}=(\dfrac{r_2}{r_1})^2\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{1\times 2^2}{(0.25)^2}\\\\F_2=64\ N$

So, the new force is 64 N if the separation between charges is 64 N.

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2 years ago

A wave has a wavelength of 13 mm and a frequency of 18 hertz. What is its speed?

labwork [276]

Velocity = Frequency x Wavelength

= 18 x 13 = 234 mm/s

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2 years ago

The speed of light is the fastest in which medium

wlad13 [49]

In vacuum, going at 2.99×10^8 m/s.

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2 years ago

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