According to the ideal gas law, a 9.585 mol sample of krypton gas in a 0.8032 L container at 504.9 K should exert a pressure of
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Answer:
The ratio of f at the higher temperature to f at the lower temperature is 5.356
Explanation:
Given;
activation energy, Ea = 185 kJ/mol = 185,000 J/mol
final temperature, T₂ = 525 K
initial temperature, T₁ = 505 k
Apply Arrhenius equation;
Where;
is the ratio of f at the higher temperature to f at the lower temperature
R is gas constant = 8.314 J/mole.K
Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356