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Answer:
The missing reagents are.
Potassium + Iodine =<u> Potassium iodide</u>
<u>Calcium</u> + oxygen = Calcium oxide
Beryllium +<u> Bromine</u> = Beryllium bromide
<u>Copper + Oxygen</u> = Copper oxide
Explanation:
The balanced equation can be written as:
1.Potassium + Iodine =<u> Potassium iodide</u>
Here K = potassium
I2 = Iodine
KI = potasssium iodide.
2.<u>Calcium</u> + oxygen = Calcium oxide
Ca = calcium
O2 = oxygen
CaO = Calcium Oxide
3.Beryllium +<u> Bromine</u> = Beryllium bromide
Here,
Be = beryllium
Br2 = bromine
BeBr2 = Beryllium Bromide
4. Copper + Oxygen = Copper oxide
Cu = Copper
O2 = oxygen
CuO = Copper Oxide
Answer: The double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.
Explanation:
Chemical compounds that have conjugated planar ring systems where there are delocalized pi-electron clouds are present in place of individual alternate and single bonds.
This means that electrons present in a double bond of alkene are in conjugation.
Therefore, we can conclude that the double bonds in an aromatic ring are not fixed in position as in an alkene. The electrons are considered to be in conjugation and are delocalized around the ring.