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PtichkaEL [24]
3 years ago
13

9.31*10^3=_*10^5 please if you could explain it as well, i’m so confused and struggling

Chemistry
1 answer:
Cloud [144]3 years ago
7 0
0.0931
9.31 x 10^3 is 9310
So 0.0931 x 10^5 equals to 9310.
When the raised power increases shift the decimal to the left hand side. If the raised power decreases then shift it to the right hand side.
Hope this helps
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How many moles of calcium are there in 5.74 x 1022 atoms of calcium?
igor_vitrenko [27]

Answer:

0.095 moles of Calcium is there in 5.74 x 1022 atoms of calcium.

Explanation:

  • As we know, 6.023*10^23 atoms of an element is equal to its atomic weight.

       And, 6.023*10^23 atoms of an element is also equal to 1 mole of the             element.

We have,

  • 6.023*10^23 atoms of element calcium equals to 1 mole of Calcium
  • 5.74*10^22 atoms of element calcium equals to

         (1/(6.023*10^.23)) * 5.74*10^22 moles of calcium

Therefore,

  • 5.74 x 1022 atoms of calcium= 0.095 moles of calcium.

6 0
4 years ago
Why does a permeable rock weather chemically at a fast rate?
ki77a [65]
<span>Water soaks into it easily and during freeze-thaw cycles would be more likely to break apart because of the water freezing and thawing inside the rock. The water freezes and expands inside the rock, causing the surface to break off in flakes from the pressure of the expanding ice inside.</span>
3 0
4 years ago
What is the mass of the oxygen in one mole of calcium phosphate
nevsk [136]

Answer:

16.00 g/mol

Explanation:

7 0
3 years ago
Read 2 more answers
Calculate the volume of the acid solution and the volume of the conjugate base solution that would be needed to prepare a buffer
bogdanovich [222]

Answer:

Explanation:

This can be contradictory, depending on whether the 0.1 M

is the total species concentration or the concentration of each of the two components. I'll consider this to be the former...

VA− = 9.125 mL

VHA = 15.875 mL

The Henderson-Hasselbalch equation is:

pH = pKa + log [A−][HA]

We have a pH 4.5

solution of acetic acid and acetate, so from there we can get the ratio of weak acid to conjugate base:

[A−][HA]=10

pH − pKa = 104.5 − 4.74 = 0.5754

Now, if the total concentration is

0.10 M , then:

[HA] + [A−] 0.5754

[HA] = 0.10 M

⇒[HA] = 0.10 M 1.0000 +0.5754

= 0.0635 M

−−−−−−−−

⇒[A−] = 0.0365 M

−−−−−−−−

and these concentrations are AFTER mixing. Since the total volume is 50 mL , or 0.050 L, the mols of each component (which are constant!) are:

nA − = 0.0365 molL × 0.050L =

0.001825 mols

−−−−−−−−−−−−

nHA = 0.0635 molL × 0.050L =

0.003175 mols

−−−−−−−−−−−−

So, if both of the starting concentrations were

0.20 M, we can find the volume they each start with:

VA − = 1 L0.20mols

A− × 0.001825mols A− = 0.009125 L = 9.125 mL

−−−−−−−−

VHA = 1 L 0.20 mols HA × 0.003175

mols HA = 0.015875 L = 15.875 mL

−−−−−−−−−

And this should make sense, because the total starting volume is

25.000 mL , the total ending volume is twice as large; the total species concentration is half the concentration that both species started with.

6 0
3 years ago
Which of the following are considered pure substances?
Helen [10]
B.Elements

Explanation: they cannot be separated
8 0
3 years ago
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