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Agata [3.3K]
3 years ago
11

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Chemistry
1 answer:
Vesna [10]3 years ago
4 0
From Q = mcΔΤ, the specific heat capacity, c, of the metal that was cooled is c = Q/mΔT = (-769 J)/(46.4 g)(30.0 °C - 101.0 °C) = 0.233 J/g °C. From the table, it appears that this is the specific heat capacity of silver. So, the metal is most like silver.

Note: The value for Q was written as a negative value in the equation as heat energy was given off by the metal when the metal was cooled (from the metal’s point of view, it’s losing heat energy).
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Soloha48 [4]
Complete balanced equation: 2HNO₃  +  Ca(OH)₂  →  Ca(NO₃)₂  +  2H₂O

Ionized equation (with spectator ions): 
   2H⁺  +  2NO₃⁻  +  Ca²⁺  +  2OH⁻   →  Ca²⁺  +  2NO₃⁻  +  2H₂O

By eliminating the ions that are the same of both sides of the equation (spectator ions):
    
2H⁺  +   2OH⁻   →    2H₂O    [Net Ionic Equation]
 
3 0
3 years ago
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If you need to reverse the following reaction in order for it to be an intermediate reaction in a Hess's law problem, what would
Olin [163]
When reversing a given reaction, we simply change the sign of the standard enthalpy change value. Therefore, the reaction will become:
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4 0
3 years ago
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Chemistry student needs 15.0 g of painting for an experiment by consulting the CRC handbook of chemistry and physiology the stud
nalin [4]

Answer:

v = 23.96 cm³

Explanation:

Given data:

Mass = 15.0 g

Density = 0.626 g/cm³

Volume = ?

Solution:

Formula:

D=m/v

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m=mass

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Now we will put the values in formula:

d = m/v

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8 0
3 years ago
What is the frequency of a wave with a wavelength of 6.40x10^4 meters?
yKpoI14uk [10]

Answer:

frequency = 0.47×10⁴ Hz

Explanation:

Given data:

Wavelength of wave = 6.4× 10⁴ m

Frequency of wave = ?

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3 × 10⁸ m/s

Now we will put the values in formula.

3 × 10⁸ m/s = 6.4× 10⁴ m × frequency

frequency = 3 × 10⁸ m/s / 6.4× 10⁴ m

frequency = 0.47×10⁴ /s

s⁻¹ = Hz

frequency = 0.47×10⁴ Hz

Thus the wave with wavelength of 6.4× 10⁴ m have 0.47×10⁴ Hz frequency.

4 0
3 years ago
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Suppose 200.0 mL of a 2.50 M solution of sodium hydroxide is combined with 400.0 mL of a 1.50 M solution of iron(III) nitrate. W
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Answer: 83%

Explanation:

The detailed solution is shown in the image attached. First we must work out the balanced reaction equation because accurate solution of the problem must be based on the stoichiometry of the reaction. From the given concentration and volume of reactants, we calculate the amount of substance reacted hence identify the limiting reactant. Lastly we use simple proportion to obtain the theoretical yield of the precipitate. This is now used to calculate the actual yield as shown in the solution attached.

6 0
3 years ago
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