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balu736 [363]
3 years ago
15

When we say an object is hot, we are describing its velocity thermal energy wavelength chemical energy?

Chemistry
1 answer:
boyakko [2]3 years ago
3 0
I think the correct answer from the choices listed above is the second option. When we say an object is hot, we are describing its thermal energy. It<span> is the </span>energy<span> that comes from heat. This heat is generated by the movement of tiny particles within an object. </span> Hope this answers the question.
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Correction?
rjkz [21]
Your answer is correct.

MgO(s) + H2O(l) ----> Mg(OH)2(aq)

:-) ;-)
5 0
3 years ago
Read 2 more answers
The element that can act like a metal when it is under tremendous pressure and is probably responsible for Jupiter and Saturn's
erastova [34]

Answer:

1. Hydrogen

Explanation:

These planets contain liquid hydrogen in their interior, while the earth has liquid iron in it.

When liquid hydrogen is in tremendous pressure enviroments, the electrons  that make up each atom of this element end up "jumping" to other atoms. These "jumps" allow liquid hydrogen to behave like a metal.

In addition, with the constant energy released by the nucleus of planets like Jupiter and Saturn, as well as their rotations, the liquid hydrogen receives induction of currents, giving rise to extremely powerful magnetic fields.

3 0
3 years ago
Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr
VikaD [51]

Answer : The value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

Explanation :

The balanced cell reaction will be,

Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)

The half-cell reactions are:

Oxidation reaction (anode) : Pb(s)\rightarrow Pb^{2+}(aq)+2e^-

Reduction reaction (cathode) : 2Ag^+(aq)+2e^-\rightarrow 2Ag(g)

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

\Delta G^o=-2\times 96500\times 0.93

\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol

Now we have to calculate the value of 'K'.

\Delta G^o=-RT\ln K

where,

\Delta G_^o =  standard Gibbs free energy  = -180 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K

K=3.6\times 10^{31}

Therefore, the value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

5 0
3 years ago
why can the combined weights of several liquids mixed in an open flask be less than but never more than the sum of all the weigh
nexus9112 [7]
Because you are never adding more than the substances created, nor are you creating any, but should a chemical reaction take place you could see the liquid change form into a gaseous state and that would result a loss of the liquid volume.
So to wrap it all up you can’t have more liquids than what is already there but you could always lose some due to a chemical change, hence the reason it says an open flask, the chemical change would not be collected, mass would be lost
4 0
2 years ago
How many formula units are present in 40.0 grams of Cu2S?
11Alexandr11 [23.1K]

Never mind, I did the problem wrong, I deeply apologize.

4 0
2 years ago
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