Question

a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find the magnitude of the thrust.

Answer 1

Answer: 24 kN

Explanation:

Given

The rocket burns propellant at the rate of

$\dfrac{dm}{dt}=3\ kg/s$

Relative ejection of gases $v=8000\ m/s$

The magnitude of thrust force is given by

$F_t=v\dfrac{dm}{dt}\\\\F_t=8000\times 3=24,000\ N\ or\ 24\ kN$