Answer:
a)Q=131.1 MJ
b)Q=54 MJ
Explanation:
Given that
Mass ,m=200 kg
Specific heat Cp=0.46 J/g°C
Cp=0.46 KJ/kg°C
Heat of fusion = 270 J/g
Heat of fusion = 270 KJ/kg
Melting point temperature = 1450°C
a)
Initial temperature = 25°C
Final temperature=1450°C
Heat required to rise temperature from 25°C to 1450°C.
Q= m CpΔT
Q=200 x 0.46 x (1450-25) KJ
Q=131,100 KJ
Q=131.1 MJ
b)
Heat required to transform from solid phase to liquid phase
Q= Mass x heat of fusion
Q=200 x 27 KJ
Q=54,000 KJ
Q=54 MJ
Answer:
aluminum bar carrying a higher load than steel bar
Explanation:
Given data;
steel abr
diameter = 5 mm
stress = 500 MPa
aluminium bar
diameter = 10 mm
stress = 150 MPa
we know
stress = laod/area
for steel bar
solving for P
P = 9817.47 N
for Aluminium bar
solving for P
P = 11790 N
aluminum bar carrying a higher load than steel bar
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