C programming fundamentals for everyone

Engineering

1 answer:

densk [106]3 years ago

6 0

Answer:I am so sorry but here are no questions, thanks for the points

Explanation:Have a nice day

You might be interested in

Hi njfrenigerg ej5gu5ngu5ntigjk5ng 5itrkgmrj gjrfgj

Vika [28.1K]

Answer:

OMG YOU SPEAK THE I LIKE UR CUT G LANGUAGE

Explanation:

wow ugyfufuyyy yufyufufyu yufuyyuuy uyyfufufu

8 0

3 years ago

If the gear ratio is 3:5 does it increase torque or speed?

Bas_tet [7]

Answer:

yes it does

Explanation:

3 0

3 years ago

Read 2 more answers

Chapter 3 skills and application

OleMash [197]

Answer:

what we have to answer please mention questions

3 0

3 years ago

A mercury thermometer has a cylindrical capillary tube with an internal diameter of 0.2 mm. If the volume of the thermometer and

vova2212 [387]

To solve this problem we will proceed to calculate the specific volume from the area of the cylinder and the sensitivity. Later we will calculate the volumetric coefficient of thermal expansion and finally we will be able to calculate the volume through the relation of the two terms mentioned above. Our values are

$\text{Sensitivity}= 2mm/\°C$

$\text{Internal diameter } d= 0.2mm$

$\text{Differential expansion of Hg } \lambda_L = 1.82*10^{-4}/\°C$

Let's start by calculating the specific volume which is given by

$v = \pi (\frac{d}{2})^2 \gamma$

Here,

d = Diameter

$\gamma$ = Sensitivity

Replacing our values we have

$v = (\frac{\pi}{4})(0.2mm)^2(2mm/\°C)$

$v = 0.0628mm^3 /\°C$

Now we will obtain the value of the volumetric coefficient of thermal expansion of mercury through the differential expansion coefficient of Hg whic is three times, then

$\lambda_V = 3\lambda_L$