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r-ruslan [8.4K]
3 years ago
13

C programming fundamentals for everyone​

Engineering
1 answer:
densk [106]3 years ago
6 0

Answer:I am so sorry but here are no questions, thanks for the points

Explanation:Have a nice day

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How does an electric circuit work?<br><br> Please give a detailed answer- thx
nydimaria [60]

Answer:

An electric current in a circuit transfers energy from the battery to the circuit components. No current is 'used up' in this process. In most circuits, the moving charged particles are negatively charged electrons that are always present in the wires and other components of the circuit.

3 0
4 years ago
Read 2 more answers
Match each term in the second column with its correct definition in the first column.
Levart [38]

Answer:

The filled in the black answers is:

1. work book

2. Spreadsheet

3. Cell

4. Sheet tabs

5. Column

6. Row

7.Cell content

8. data

9. Formula

10. Constant value

11. Number value

12. Cell address

7 0
3 years ago
For a fluid with a Prandtl Number of 1000.0, the hydrodynamic layer is thinner than the thermal boundary layers. a) True b) Fals
kvv77 [185]

Answer:

(b)False

Explanation:

Given:

 Prandtl number(Pr) =1000.

We know that   Pr=\dfrac{\nu }{\alpha }

  Where \nu is the molecular diffusivity of momentum

             \alpha is the molecular diffusivity of heat.

 Prandtl number(Pr) can also be defined as

    Pr=\left (\dfrac{\delta }{\delta _t}\right )^3

Where \delta is the hydrodynamic boundary layer thickness and \delta_t is the thermal boundary layer thickness.

So if Pr>1 then hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

In given question Pr>1 so  hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

So hydrodynamic layer will be thicker than the thermal boundary layer.

8 0
4 years ago
A well-insulated, rigid vessel contains 3 kg of saturated liquid water at 40°C. The vessel also contains an electrical resistor
fenix001 [56]

Answer:

The final temperature in the vessel after the resistor has been operating for 30 min is 111.67°C

Explanation:

given information:

mass, m = 3 kg

initial temperature,  T₁ = 40°C

current, I = 10 A

voltage, V = 50 V

time, t = 30 min = 1800 s

Heat for the system because of the resistance is

Q = V I t

where

V = voltage (V)

I = current (A)

t = time (s)

Q = heat transfer to the system (J)

so,

Q = V x I x t

   = 50 x 10 x 1800

   = 900000

   = 9 x 10⁵ J

the heat transfer in the closed system is

Q = ΔU + W

where

U = internal energy

W = work done by the system

thus,

Q = ΔU + W

9 x 10⁵ = ΔU + 0, W = 0 because the tank is a well-insulated and rigid.

ΔU = 9 x 10⁵ J = 900 kJ

then, the energy change in the system is

ΔU = m c ΔT

ΔT = ΔU / m c, c = 4.186 J/g°C

     = 900 / (3 x 4.186)

     = 71.67°C

so,the final temperature (T₂)

ΔT = T₂ - T₁

T₂ = ΔT + T₁

    = 71.67°C + 40°C

    = 111.67°C

7 0
3 years ago
The following are related to wastewater treatment:
Paraphin [41]

Answer:

A. - Primary wastewater treatment: the physical treatment process which is used to in order to get rid of suspended solids that can settle from wastewater.

- Secondary wastewater treatment: treatment processes remove waste organic ( which are once living/biological) material from wastewater, usually by the use of a biological treatment process.

-Tertiary wastewater treatment: Tertiary treatment isn't needed at all wastewater treatment plants, and the place it is needed, it may be different from one plant to another, depending on the type of water contamination that must be removed.

B. Primary treatment: Approximately 35% of the incoming biochemical oxygen demand (BOD).

Secondary treatment : Approximately 85% of biochemical oxygen demand (BOD).

C. - Activated Sludge, Rotating biological contractors.

Explanation:

A. Primary wastewater treatment refers to sedimentation, the physical treatment process which is used to in order to get rid of suspended solids that can settle from wastewater. The main goal of primary treatment is to remove organic and inorganic solids that settles by sedimentation, and by act of skimming removed materials end up floating.

Secondary wastewater treatment processes remove waste organic ( which are once living/biological) material from wastewater, usually by the use of a biological treatment process. The goal of secondary treatment is the further treatment of the effluent from primary treatment in order to get rid of the residual organics and suspended solids.

Advanced wastewater is quite in between. Tertiary treatment isn't needed at all wastewater treatment plants, and the place it is needed, it may be different from one plant to another, depending upon the type of water contamination that must be removed. Advanced treatment processes can be combined with primary or secondary treatment or used instead of secondary treatment.

B. Primary treatment: Approximately 35% of the incoming biochemical oxygen demand (BOD).

Secondary treatment : Approximately 85% of biochemical oxygen demand (BOD).

C.

-Activated Sludge: The activated sludge process is a kind of wastewater treatment process for treating sewage/industrial wastewaters by the use of aeration and a biological floc which consists of bacteria and protozoa.

- Rotating biological contactor: Rotating biological contactors (RBCs) are fixed-film reactors that have similarities with biofilters in the sense that organisms are attached to support media.

Activated sludge is a suspended process, which is when the biomass is mixed with the sewage while in rotating biological contractor, the biomass grows on the media and then, the sewage passes over the surface.

6 0
4 years ago
Read 2 more answers
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