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vredina [299]
3 years ago
11

The map shows the distribution of dairy farms across the lower 48 of the United States. Each dot on the map represents approxima

tely ten dairy farms.
Engineering
1 answer:
yan [13]3 years ago
6 0

Answer:

1. Large swathes of land is being devoted to the cultivation of corn and cultivation of nutritious grasses.

2. Vegetation and Rainfall

Explanation:

1. One characteristic land-use feature associated with the dairy farms is the use of large swaths of land to grow corn and nutritious alfalfa grass. Earlier, these lands were devoted to the cultivation of temperate wheat. However, the success of commercial dairy farming in the region has led to the introduction of extensive farming methods where large farms are devoted to corn and alfalfa production. Application of manures, usage of machines is very high and the overall yield of the farms is very high but yield per unit of land is low.

2. Two geographic features not shown on the map that corroborates to the above concentration pattern are-

Vegetation- Temperate grassland (Prairie) of these regions provides large and extensive ground for the cultivation of fodder grass. Prairie supports the cultivation of these grasses.

Rainfall- These areas receive plenty of rainfall from humongous freshwater lakes in their vicinity. This rainfall proves crucial for cultivation for animal feeds.

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A person is planning a bungee jump from a 40 meter high bridge. Under the bridge is a river with crocodiles, so the person does
Nonamiya [84]

Answer:

a. l = 19.7m, b. 18.55m, c. Impact Force = 3889.84 N

Explanation:

The total energy of the system when the person is at top of the bridge is

Potential energy = mgh, Kinetic energy = 0

The total energy of the  system when the person reaches just above the surface

Potential energy = 0, Kinetic energy = 0, Spring energy = ½ K X2, where k is the spring constant and X is the deflection

Applying conservation of energy

mgh = 0 + 0 + ½ K X²

80 x 9.81 x 40 = ½ (3600/l) X²

31392 = ½ (3600/l) X²

We can also conclude that

l+ X + 1.75 = 40

l + X = 38.25

a. <u>Substitute the value of x from above into the energy conversion expression</u>

31392 = ½ (3600/l)(38.25 - l)²

31392 x 2/3600 = (38.25 + l² – 2l(38.25))/l

17.44l = l2 – 76.5l + 38.25²

l² – 76.5l – 17.44l +1463.0625 = 0

Solving for l we get

L = 19.7

Hence, length of the rope is 19.7m

b. <u>The deflection is calculated by using the relation between l and X</u>

L + X = 38.25

X = 38.25 – 19.7 = 18.55m

c. <u>The impact force is calculated using the impact force formula which relates the impact force with the deflection</u>

F = KX

F = (3600/l) . X

F = (3600/19.7) . (18.55) = 3889.84 N

Thus, the impact force is 3889.84 N

3 0
3 years ago
8. The operation of a TXV is controlled by the
Katena32 [7]
Answer should be C hopefully
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River models are used to study many different types of flow situations. A certain small river has an average width and depth of
slavikrds [6]

Answer: 7ft x21 I’d be right but yes I am

Explanation: because it is Welty

4 0
3 years ago
QUESTION:<br> Which of the following statements about Haas lathes is true?
Usimov [2.4K]
What are the choices
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3 years ago
Read 2 more answers
A semiconductor diode has the following parameters: Is = 4.0×10-13 Amps, n = 1.35, and is operated at a temperature of T = 270K.
andrew-mc [135]

Answer:

V_T=0.02328V\\I=7.77\times 10^{-5} A \\V_D=0.77V

Explanation:

Let's use Shockley ideal diode equation which relates the current intensity and the potential difference:

I=I_S (e^{\frac{V_D}{nV_T} } -1)

Where:

I=Diode\hspace{3}current\\I_S=Reverse\hspace{3}bias\hspace{3}saturation\hspace{3}current\\V_D=Voltage\hspace{3}across\hspace{3}the\hspace{3}diode\\V_T=Thermal\hspace{3}voltage\\n=Ideality\hspace{3}factor

Thermal voltage at any temperature it is a known constant defined by:

V_T=\frac{kT}{q}

Where:

k= Boltzmann\hspace{3}constant \approx1.38\times 10^{-23} \\T=Absolute\hspace{3}temperature\\q=Charge\hspace{3}of\hspace{3}an\hspace{3}electron \approx 1.6\times 10^{-19} C

(a)

Using the data provided:

V_T=\frac{(1.38\times 10^{-23})*(270) }{1.6\times 10^{-19} }= 0.0232875V

(b)

Using the data provided and Shockley ideal diode equation

I=(4\times 10^{-13} )*(e^{\frac{0.6}{1.35*0.0232875} }-1)=7.773505834\times10^{-5}\approx 7.77  \times10^{-5}A\\I\approx0.0777mA

(c) Let's isolate V_D from Shockley ideal diode equation:

I=I_S (e^{\frac{V_D}{nV_T} } -1)\\\\Multiply\hspace{3}both\hspace{3}sides\hspace{3}by\hspace{3}I_S\\\\\ \frac{I}{I_S} = e^{\frac{V_D}{nV_T} } -1\\\\Add\hspace{3}1\hspace{3}both\hspace{3}sides\\\\

\frac{I}{I_S} +1 =e^{\frac{V_D}{nV_T} } \\\\Take\hspace{3}the\hspace{3}natural\hspace{3}logarithm\hspace{3}of\hspace{3}both\hspace{3}sides\\\\\frac{V_D}{nV_T} =log(\frac{I}{I_S} +1) \\\\Multiply\hspace{3}both\hspace{3}sides\hspace{3}by\hspace{3}nV_T\\\\V_D=nV_T*log(\frac{I}{I_S} +1)

Finally, using the data provided:

V_D=(1.35)(0.0232875)*log(\frac{20\times 10^{-3} }{4\times 10^{-13} }+1)=0.77448729\approx 0.77V

7 0
3 years ago
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