A problem that will be handled by a procedure is described by an input-output specification.
<h3>What is input and output specification?</h3>
- An input-output specification outlines the issue that a procedure will try to solve. The input part and the output part are its two components.
- The input component outlines the kind of data object that should be provided for each actual argument as well as any presumptions that the process might make.
- A technical specification known as an output specification defines the project scope primarily through performance-based requirements.
- It is used to assess technical compliance and serves as the technical cornerstone of both the procurement and delivery phases.
- Known as classical specifications, they outline the precise services to be provided, sometimes in great detail, along with the standard you must meet and the approach you must take to meet the standard.
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Answer:
<u>Option-(A)</u>
Explanation:
<u>Typical applications for the high carbon steels includes the following;</u>
It is heat treatable, relatively large combinations of mechanical characteristics. Typical applications: railway wheels and tracks, gears, crankshafts, and machine parts.
The answer is D-all choices
Answer:
Cylindrical
Explanation:
<em>A cylindrical grinder </em><em>is a tool for shaping the exterior of an item. Although cylindrical grinders may produce a wide range of forms, the item must have a central axis of rotation. Shapes such as cylinders, ellipses, cams, and crankshafts are examples of this.</em><em> Cylindrical grinding</em><em> machines are specialized grinding machines that are used to process cylinders, rods, and similar workpieces. The cylinders revolve in one direction between two centers, while the grinding wheel or wheels are close together and rotate in the other direction.</em>
Answer:
N = 38546.82 rpm
Explanation:
= 150 mm

= 17671.45 
= 250 mm

= 49087.78 
The centrifugal force acting on the flywheel is fiven by
F = M (
-
) x
------------(1)
Here F = ( -UTS x
+ UCS x
)
Since density, 





∴
-
= 50 mm
∴ F = 
F = 33618968.38 N --------(2)
Now comparing (1) and (2)

∴ ω = 4036.61
We know


∴ N = 38546.82 rpm