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3 years ago

Why is a saturated solution of magnesium hydroxide less basic than a saturated solution of potassium hydroxide?

Chemistry

1 answer:

soldier1979 [14.2K]3 years ago

8 0

Answer:

letter C I'm not sure to my answer but hope it can hrlp

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lana66690 [7]

Answer:

Explanation:

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3 years ago

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Doy CORONITA a quien me ayude rapido que es un examen porfaaa

rodikova [14]

Answer:

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3 years ago

A buffer is composed of nh3 and nh4cl. How would this buffer solution control the ph of a solution when a small amount of a stro

Shkiper50 [21]

Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of $OH^{-}$ and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

$NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)$

So, $OH^{-}$ is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of $OH^{-}$ increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of $OH^{-}$ and keep same equilibrium constant.

Therefore excess amount of $OH^{-}$ combines with $NH_{4}^{+}$ to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

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3 years ago

Na + Cl --> NaCl

dalvyx [7]

Answer:

38.152 g NaCl would be produced.

Explanation:

$\frac{(23 + 35.5) \times 15}{23} \\ = 38.152 \: \: g$

Mark me as Brainliest 

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2 years ago

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Calculate how much heat is absorbed by a sample that weighs 12 kilograms, has a specific heat of 0.231 kg/CJ, and is heated from

Andrei [34K]

Answer:

97 J

Explanation:

Step 1: Given data

Mass of the sample (m): 12 kg

Specific heat capacity (c): 0.231 J/kg.°C (this can also be expressed as 0.231 J/kg.K)

Initial temperature: 45 K

Final temperature: 80 K

Step 2: Calculate the temperature change

ΔT = 80 K - 45 K = 35 K

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.231 J/kg.K × 12 kg × 35 K = 97 J

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3 years ago