What is the volume of 2.2 moles of gas at STP??? Pleaseeeee help

Ted used a balance scale to weigh a 2.233 g sample of copper sulfate. Which of these measurements made by Ted is the most accura

Vika [28.1K]

There’s only one measurement the question doesn’t make sense

6 0

3 years ago

Identify the chemical reactions as endothermic, exothermic, or neither. An egg cooking: A candle burning: Plaster and water comb

lianna [129]

Answer :

An egg cooking is an endothermic reaction.

A candle burning and Plaster & water combining and becoming warm are exothermic reaction.

Salt being added to water, with no change in temperature neither endothermic nor exothermic reaction.

Explanation :

Endothermic reaction : It is a type of reaction in which energy is absorbed in the form of heat from the surroundings.

Exothermic reaction : It is a type of reaction in which energy is released in the form of heat from the system.

An egg cooking : In this process, the energy is absorbed in the form of heat.

A candle burning and Plaster & water combining and becoming warm : In both the process, the energy is released in the form of heat.

Salt being added to water, with no change in temperature : In this process, neither energy released nor absorbed.

5 0

3 years ago

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Annabelle was explaining the carbon cycle to her friend. She said that all the carbon

vagabundo [1.1K]

Answer: O2+6H12O6=CO2+ENERGY(ATP)

I DON'T THINK SHE IS CORRECT

Explanation:

5 0

4 years ago

How many grams of hydrogen gas get produced if 10 g of aluminum reacts?

Degger [83]

Answer:

9.8

Explanation:

8 0

3 years ago

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

Answer: The mass of glucose in final solution is 0.420 grams

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

3 years ago