Answer:
Option C = 6 of carbon react with 16 g of oxygen.
Explanation:
In given question it is stated that 12 g of carbon react with 32 g of oxygen to produce carbon dioxide. The other combination option c is also true because in this, the quantity of both reactant is just half from the given quantity. Which means that if 100 % product is obtained from the 12 g of carbon and 32 g of oxygen then by taking the half amount of reactant the product will be half i.e 50% .
This combination is true because the ratio of both reactant are justified.
Carbon 12g + Oxygen 32g → carbon dioxide
C : O 1 : 2.6
Option C:
Carbon ( 12/2 =6g ) + Oxygen (32/2 = 16g) → Carbon dioxide
C : O 1 : 2.6
Answer:
The value of the equilibrium constant = 5.213
Explanation:
Here 
(equilibrium constant) is referred to as the partial pressure of product divided by the partial pressure of reactant with each pressure term raised to power that is equal to its stoichiometric coefficient in balanced equation
.
As such only gas appear in expression as solids takes a value of 1;
SO ; in the given equation from the question:
2 A (g) + B (s) ----> 2 C(s) + D (g)
![K_p = \dfrac{[D]}{[A]^2}](https://tex.z-dn.net/?f=K_p%20%3D%20%5Cdfrac%7B%5BD%5D%7D%7B%5BA%5D%5E2%7D)
The value of the equilibrium constant = 5.213
3 atoms! Glad I can help! :)
Since that is a lengthy one I to have the same problem in chem. I always trust google and ask question but question of the elements of the periodic table and one by one it will give you the answer and will tell you the formula and the cations
Answer is: elements in group 1 will lose electrons to obtain a noble gas structure. They will lose 1 electron.
For example ₃Li 1s²2s¹ will lose one electron from 2s oribtal to obtain helium structure ₂He 1s².
Or sodium ₁₁Na 1s²2s²2p⁶3s¹ will also lose one electron to obtain neon structure ₁₀Ne 1s²2s²2p⁶.
