Answer:
Ocean waves contain tremendous energy potential. Wave power devices extract energy directly from the surface motion of ocean waves. In many areas of the world, the wind blows with enough consistency and force to provide continuous waves along the shoreline.
Specific heat capacity is the amount of energy required to raise one gram of substances by 1 degree celsius . Therefore specific heat capacity for tatanium is 89.7j /( 33.0g x5.2 degree celsius) = 0.52j/g degree celcius
Molar mass for tatanium is 47.9 g/mole
heat is therefore 47.9 g/mole x 0.52j/g =24.9j/mole
Answer:
C)52g KCl in 100g water at 80°C
Explanation:
A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.
A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.
From the solubility curve in the attachment below:
A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.
B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.
C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.
D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.
Answer:
The molarity of this solution is 0.156 M
Explanation:
Step 1: Data given
Mass of Ba(OH)2 = 1.90 grams
Molar mass Ba(OH)2 = 171.34 g/mol
Volume of the solution = 71.1 mL = 0.0711 L
Step 2: Calculate moles Ba(OH)2
Moles Ba(OH)2 = mass Ba(OH)2 / molar mass Ba(OH)2
Moles Ba(OH)2 = 1.90 grams / 171.34 g/mol
Moles Ba(OH)2 = 0.0111 moles
Step 3: Calculate molarity
Molarity solutin = moles Ba(OH)2 / volume solution
Molarity solution = 0.0111 moles / 0.0711 L
Molarity solution = 0.156 M
The molarity of this solution is 0.156 M