On a victim, a circular entrance wound with black edges is found. Which most likely caused this wound?
2 answers:
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Answer:
a) The slope of the line of best fit plot = -12629.507
b) ΔH∘ = 105 kJ
c) Intercept of the line of best fit plot = 39.099
d) ΔS∘ = 325.1 J/K
e) Option A is correct.
Solubility will increase as temperature increases, because as T increases the (−ΔH∘/RT) term becomes smaller therefore K will get larger.
f) Option D is correct. All of the options are correct.
Explanation:
The complete question is presented in the first attached image to this question. This complete question has the data readings required to plot the graph.
The second attached image has the plotted graph and the regression analysis to obtain the line of best fit.
The equation of the line of best fit obtained is
y = -12629.507x + 39.099
Comparing the given expression for the question with the equation of a straight line
ln (K) = (−ΔH∘/RT) + (ΔS∘/R)
y = mx + c
y = In K
Slope = m = (−ΔH∘/R)
x = (1/T)
Intercept = c = (ΔS∘/R)
So, to answer the question now
a) The slope of the line of best fit plot = -12629.507
b) Slope = (−ΔH∘/R)
(−ΔH∘/R) = -12629.507
But R = molar gas constant = 8.314 J/mol.K
ΔH∘ = 12629.507 × 8.314 = 105,001.721198 J = 105,002 J = 105 kJ
c) Intercept of the line of best fit plot = 39.099
d) Intercept = (ΔS∘/R)
(ΔS∘/R) = 39.099
ΔS∘ = 39.099 × 8.314 = 325.069086 J/K = 325.1 J/K
e) Do you expect the solubility of Borax to increase or decrease as temperature increases?
Solubility will increase as temperature increases, because as T increases the (−ΔH∘/RT) term becomes smaller therefore K will get larger.
f) Why was it necessary to make sure that some solid was present in the main solution before taking the samples to measure Ksp? Select the option that best explains why.
A. To make sure no more sodium borate would dissolve in solution.
B. To ensure the dissolution process was at equilibrium.
C. To make sure the solution was saturated with sodium and borate ions.
D. All of the above
Hope this Helps!!!
Answer:
4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium
Explanation:
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:
- HCl: 2 moles
- Na: 1 mole
- NaCl: 2 moles
- H₂: 1 mole
You know the following masses of each element:
- H: 1 g/mole
- Cl: 35.45 g/mole
- Na: 23 g/mole
So, the molar mass of each compound participating in the reaction is:
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
- Na: 23 g/mole
- NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
- H₂: 2* 1 g/mole= 2 g/mole
Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:
- HCl: 2 moles* 36.45 g/mole= 72.9 g
- Na: 1 mole* 23 g/mole= 23 g
- NaCl: 2 moles* 58.45 g/mole= 116.9 g
- H₂: 1 mole* 2 g/mole= 2 g
So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?
mass of H₂= 4.8 g
<u><em>4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium</em></u>