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Oliga [24]
3 years ago
6

Which sample of water contains particles having the highest average kinetic energy?

Chemistry
1 answer:
34kurt3 years ago
8 0
I think the answer is b
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Louisa put a bowl of water and a bowl of sand in the sun. She put a thermometer in each bowl. Then she recorded the temperature
Helen [10]

The experiment that was carried out by Louisa goes to show us that different materials heat up at different rates.

<h3>What is the specific heat capacity?</h3>

The term specific heat capacity just goes to show us the amount of heat that must be absorbed before the temperature of an object would rise by 1 K. In this case, we can see that we have been told that the after 30 minutes, the sand had heated more than the water. This simply implies that the energy that the sand and the water absorbed was able to increase the temperature of the sand mush more than it increased the temperature of the water.

Thus we can see that the heat capacity of the sand is much less than the heat capacity of the water since the sand could be able to be heated up much faster than the the water could be heated up.

Learn more about heat capacity:brainly.com/question/28302909

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8 0
1 year ago
What mass of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.
iren [92.7K]

91.4 grams

91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

C = mol/volume

2.45M=mol/0.5L

2.45M⋅0.5L = mol

mol = 1.225

Convert no. of moles to grams using the atomic mass of K + Cl

1.225mol * \frac{39.1+35.5}{mol}

mol=1.225

=1.225 mol . \frac{74.6g}{mol}

=1.225 . 74.6

=91.4g

therefore, 91.4 grams of kcl in grams must be added to 500 ml of a 0. 15 m kcl solution to produce a 0. 40 m solution.

What is 1 molar solution?

In order to create a 1 molar (M) solution, 1.0 Gram Molecular Weight of the chemical must be dissolved in 1 liter of water.

58.44 g make up a 1M solution of NaCl.

To learn more about molar solution visit:

brainly.com/question/10053901

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3 0
1 year ago
What volume of 0.140 HCl is needed to neutralize 2.58 of Mg(OH)2<br> ? ...?
elena-s [515]
To make a first step you have to know the balanced form for neutralization formula: Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)&#10;
According to this, you can <span>calculate what you are being asked :</span>0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl
Then we have : 0.140MHCl=0.140(mol/L)HCl
Hope everything is clear, here is the exact answer you need : V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl&#10;

8 0
3 years ago
Does an acid gain or lose a hydrogen cation, H+, during an acid-base reaction?
elena-s [515]

It loses an H+.

The bronsted lowry definition for an acid is that an acid is a H+ donor, or giver. So, during an acid based reaction, an acid would lose a H+.

Lose an H+.

6 0
3 years ago
Which solution has the lower freezing point in each of the following pairs? (a) 11.0 g of CH3OH in 100. g of H2O or 22.0 g of CH
Evgen [1.6K]

Answer:

See explanation

Explanation:

(a)

From the data provided;

Mass of methanol =11.0 g

Mass of solvent (H2O) =100 g = 0.1 kg

Molar mass of CH3OH =32.04 g/mol

Number of moles of solute = 0.343 mol

molality(m) of methanol = 3.43 m

Also,

Mass of ethanol =22.0 g

Mass of solvent (H2O) =200 g = 0.2 kg

Molar mass of C2H5OH =46.068 g/mol

Number of moles of solute = 0.477 mol

molality(m) of ethanol= 2.38 m

The greater the concentration of a solution, the higher the freezing point of solvent will be depressed. Therefore, higher molality, leader to a greater decrease of the freezing point.

Therefore, the freezing point of methanol CH3OH/H2O is lower than the freezing point of ethanol.

b)

Mass of solvent = 1 kg

Mass of water = 20g or 0.02 Kg

Molar mass of water = 18 gmol-1

Number of moles of solute = 20g/18 gmol-1 = 1.11 moles

Molality= 1.11 moles/1 kg = 1.11 m

Also;

Mass of ethanol = 20 g = 0.02 kg

Mass of solvent = 1.00 Kg

Molar mass of solute = 46 gmol-1

Number of moles of solute = 20g/ 46 gmol-1 = 0.43 moles

Molality= 0.43 moles/ 1 kg = 0.43 m

The greater the concentration of a solution, the higher the freezing point of solvent will be depressed. Therefore, higher molality, leader to a greater decrease of the freezing point.

Therefore, the freezing point of water H2O/CH3OH is lower than the freezing point of ethanol.

3 0
3 years ago
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