Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Answer:34%
Step-by-step explanation:I think this is right but I don’t really understand
In this question, we're trying to find cost of one sandwich.
To find this, we must make a systems of equation from the given information:
We would represent sandwiches as "s" and drinks as "d".
Systems of equations:
6s + 4d = 53
4s + 6d = 47
Solve for s:
6(6s + 4d = 53)
-4(4s + 6d = 47)
36s + 24d = 318
-16s - 24d = -188
--------------------------
20s = 130
Divide both sides by s
s = 6.50
This means that one sandwich costs $6.50
Answer:
$6.50
Answer:
w = -10.5
Step-by-step explanation:
p = 21 +2w
get 2w by its self
p= 21 + 2x
-21 -21
p - 21 = 2w
cancel out p
p(0) - 21 = 2w
-21 = 2w
divide both sides by 2
w= -10.5
Hope this helps!!!
I can't see any table, is there a picture?
but something like 45x would be near the answer
