Answer: it’s B -3x-5
Explanation: just answered it and got it correct.
Answer:
Explanation:
since the ball was thrown at 0s and caought again at 5 s. applying eqaution of motion.
0 = u×5 - 
×10×5×5
solving the eqaution we gaet initial velocity u = 25 m/s.
there fore total energy E = ×m×25×25 J
where m is the mass of the ball according to conservation of energy E remains constant
conservation of energy:
kinetic + potential energy of the ball = E
kinetic energy = E - mgh 
1
h = 
applying ot in the eqaytion 1
kinetic energy = e - 
2
Therefore kinetic energy vs height will be a straight line with negative slope and kinetic energy vs time will be parabola that is open upward.
Answer:
The capacitor will charge
Explanation:
When the capacitor is connected to the circuit containing the battery and the resistor, charges (electrons) will start flowing through the circuit, pushed by the electromotive force produced by the battery. In particular:
- electrons will flow from the negative terminal of the battery to one plate of the capacitor
- electrons will flow from the other plate of the capacitor to the positive terminal fo the battery
(It's important to keep in mind that the electrons never cross the gap between the plates of the capacitor.)
Therefore, negative charge will accumulate on one plate of the capacitor and positive charge will accumulate on the other plate: and so, there will be an increasing potential difference across the plates of the capacitor. Due to this increasing potential difference, it will become more and more difficult for the battery to "push" electrons on the negative plate (and to remove them from the other plates), so the current in the circuit will keep decreasing.
The process stops when the potential difference across the gap of the capacitor is equal to the e.m.f. of the battery: at this point, there is no more current in the circuit, and the capacitor is said to be fully charged.
Answer:
Explanation:
Given
density
Diameter(d)=2.4 mm
time taken=10 s
Distance moved(h)=0.75 m
At terminal velocity Drag force is equal to Weight
Volume of ball
Mass of ball
Also for spherical bodies drag force is equal to Stock Force
Where 
= Terminal velocity
<span>forms as pices of loose material is carried by water or wind, settles out into layers and is then pressed or cemented together</span>
