Answer:
The graph with solution is shown below.
Step-by-step explanation:
We need to find the
and
for given equation.
For
, substitute 
Considering inequality sign as equality and simplifying,
, point is 
Similarly,
For
, substitute 
We get,
, point is 
We locate this two points on the graph now and join them.
The joining line will be dotted as the inequality has just 'greater than' symbol. The region above the dotted line is the solution to graph.
(3*j)-8
I thinkkkk... I’m positive tho
Answer: 
Step-by-step explanation:
We know that the standard quadratic equation is ax^2+bx+c=0
Let's compare all the given equation to it and , find discriminant.
1. a=2, b= -7, c=-9
So it has 2 real number solutions.
2. a=1, b=-4, c=4

So it has only 1 real number solution.
3. a=4, b=-3, c=-1

So it has 2 real number solutions.
4. a=1, b=-2, c=-8
So it has 2 real number solutions.
5. a=3, b=5, c=3

Thus it does not has real solutions.
To more easily graph this, convert it to slope-intercept form (y = mx + b, where m is the slope and b is the y-intercept):
x - y = 1
-y = -x + 1
y = x - 1
The slope is 1 and the y-intercept is -1. To graph this, plot the point (0, -1) and count 1 unit down and 1 unit to the right. Do this once more, connect the points, and you have your line.
Hope this helps.