Answer:
The image of the point (1, -2) under a dilation of 3 is (3, -6).
Step-by-step explanation:
Correct statement is:
<em>What are the coordinates of the image of the point (1, -2) under a dilation of 3 with the origin.</em>
From Linear Algebra we get that dilation of a point with respect to another point is represented by:
(Eq. 1)
Where:
- Reference point with respect to origin, dimensionless.
- Original point with respect to origin, dimensionless.
- Dilation factor, dimensionless.
If we know that 
, 
and 
, then the coordinates of the image of the original point is:
![\vec P' = (0,0) +3\cdot [(1,-2)-(0,0)]](https://tex.z-dn.net/?f=%5Cvec%20P%27%20%3D%20%280%2C0%29%20%2B3%5Ccdot%20%5B%281%2C-2%29-%280%2C0%29%5D)
The image of the point (1, -2) under a dilation of 3 is (3, -6).
9514 1404 393
Answer:
- vertex: (7.5, 2.25)
- f(x) = -(x -7.5)² +2.25
Step-by-step explanation:
My favorite "technology" for problems like this is the Desmos graphing calculator app or web service. It easily displays the vertex (and/or zeros) of the function.
Of course, vertex form is ...
f(x) = a(x -h)² +k . . . . . . . . vertex (h, k), leading coefficient 'a'
The solution is found by reading the graph and putting the numbers in the formula. The leading coefficient is copied from the standard form equation.
- vertex: (7.5, 2.25)
- f(x) = -(x -7.5)² +2.25
Make a graph and put a point at exactly (1,2) and then make a like at y=3 make a line through the point and you'll see that this is an undefined equation x cant equal all those numbers
When n = 1 first term = -6
n = 2 second term = 0
n = 3 third term = 6
n = 4 4th term = 12
so we have an Arithmetic sequence first term = -6 and common difference = 6
Sum 14 terms = (14/2)[2*-6 + (14-1)*6]
= 462 answer
Answer:
0.666666667
Step-by-step explanation:
