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Sonja [21]
4 years ago
11

Goertz Corporation has an activity-based costing system with three activity cost pools--Machining, Order Filling, and Other. In

the first stage allocations, costs in the two overhead accounts, equipment depreciation, and supervisory expense are allocated to the three activity cost pools based on resource consumption. Data used in the first stage allocations follow:
Overhead costs:
Equipment depreciation $ 51,000
Supervisory expense $ 3,000
Distribution of Resource Consumption Across Activity Cost Pools:
Activity Cost Pools
Machining Order Filling Other
Equipment depreciation 0.40 0.10 0.50
Supervisory expense 0.20 0.30 0.50
Machining costs are assigned to products using machine-hours (MHs) and Order Filling costs are assigned to products using the number of orders. The costs in the Other activity cost pool are not assigned to products. Activity data for the company's two products follow:
Activity:
MHs (Machining) Orders (Order Filling)
Product J3 9,100 100
Product F7 900 900
Total 10,000 1,000
Finally, the costs of Machining and Order Filling are combined with the following sales and direct cost data to determine product margins.
Sales and Direct Cost Data:
Product J3 Product F7
Sales (total) $ 145,200 $ 90,700
Direct materials (total) $ 81,400 $ 38,600
Direct labor (total) $ 37,700 $ 42,400
How much overhead cost is allocated to the Order Filling activity cost pool under activity-based costing?
a. $5,100
b. $900
c. $27,000
d. $6,000
Business
1 answer:
4vir4ik [10]4 years ago
4 0

Answer: D. $6,000

Explanation:

Given the following :

Activity cost pool

- - - - - - - - - - - - - - - - - - Machining Order Filling Other

Equipment depreciation 0.40 - - - - - 0.10 - - 0.50

Supervisory expense - - 0.20 - - - - - 0.30 - - 0.50

First stage allocation:

Overhead cost

Equipment depreciation - $51,000

Supervisory expense - $3000

Order filling:

Equipment depreciation - $51,000 × 0.1 = $5100

Supervisory expense - $3000 × 0.3 = $900

Total overhead - $( 5100 + 900) = $6,000

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Solution

(a)In a survey of 1,364 people, 395 were females who used social media and 232 did not. of males 232 use social media and 355 did not

To make or develop a probability table, take each group and divide their number by their total for example female that use social media is 395 of a total of 1364

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The probability that a woman uses social media in the survey is 0.2896

so,

                                  A              B              T

Female                  0.2896       0.2133      0.5029

Male                      0.2368       0.2603     0.4971

Total                      0.5264      0.4736       1.00

(b) To find the probability  of a surveyed person being a female, we divivde the total number of females by the whole number, shown below

686/1364 = 0.5029

(c)Conditional probability is defined using the formula which is shown below:

P(A/B) = P(A∩B)/P(B)-------(1)

Where P(A∩B) is the probability of females that use social media 0.2896 and P(B) is the total female probability which is 0.5029

Now we substitute the values in the equation 1 and calculate the probability as shown below:

P(A/B) = 0.2896/0.5029 =0.5758

the conditional probability that are surveyed person is female and uses social media is 0.5758

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