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Andrew [12]
4 years ago
9

Which description tells the length of time it takes for a planet to revolve around the sun?

Physics
1 answer:
s344n2d4d5 [400]4 years ago
5 0
A) the length of its year 
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Which property of metals allows corrosion to take place? reactivity malleability ductility conductivity Description
horrorfan [7]
Your best bet would be reactivity
7 0
3 years ago
Read 2 more answers
Air enters a turbine operating at steady state at 8 bar, 1400 K and expands to 0.8 bar. The turbine is well insulated, and kinet
vladimir2022 [97]

To solve this problem it is necessary to apply the concepts related to the adiabatic process that relate the temperature and pressure variables

Mathematically this can be determined as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

Where

T_1 =Temperature at inlet of turbine

T_2 = Temperature at exit of turbine

P_1 = Pressure at exit of turbine

P_2 =Pressure at exit of turbine

The steady flow Energy equation for an open system is given as follows:

m_i = m_0 = m

m(h_i+\frac{V_i^2}{2}+gZ_i)+Q = m(h_0+\frac{V_0^2}{2}+gZ_0)+W

Where,

m = mass

m_i = mass at inlet

m_0= Mass at outlet

h_i = Enthalpy at inlet

h_0 = Enthalpy at outlet

W = Work done

Q = Heat transferred

V_i = Velocity at inlet

V_0= Velocity at outlet

Z_i= Height at inlet

Z_0= Height at outlet

For the insulated system with neglecting kinetic and potential energy effects

h_i = h_0 + W

W = h_i -h_0

Using the relation T-P we can find the final temperature:

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^{(\frac{\gamma-1}{\gamma})}

\frac{T_2}{1400K} = (\frac{0.8bar}{8nar})^{(\frac{1.4-1}{1.4})}

T_2 = 725.126K

From this point we can find the work done using the value of the specific heat of the air that is 1,005kJ / kgK

So:

W = h_i -h_0

W = C_p (T_1-T_2)

W = 1.005(1400-725.126)

W = 678.248kJ/Kg

Therefore the maximum theoretical work that could be developed by the turbine is 678.248kJ/kg

5 0
4 years ago
13) Fred is travelling 3.4 m/s and decelerates at a rate of 0.83 m/s until he comes to a stop
Finger [1]

Answer:

<h2>Tt will take 4.04 seconds</h2>

Explanation:

In this problem/exercise, we are going to apply the newtons first equation of motion to solve for the time taken

Given that

final velocity= 3.4m/s

initia velocity u= 0m/s

deceleration= 0.84 m/s^2

time t= ?

applying

v=u+at

Substituting our given data into the expression above we have

3.4=0+0.84t

3.4=0.84t

divide both sides by 0.84 we have

3.4/0.84= t

t= 4.04 seconds

3 0
3 years ago
A scooter is accelerated from rest at the rate of 8m/s . How long will it take to cover a distance of 32m?​
TiliK225 [7]
  • <em>S</em><em>peed </em><em>=</em><em> </em><em>8</em><em> </em><em>m/</em><em>s</em>
  • <em>Distance</em><em> </em><em>=</em><em> </em><em>3</em><em>2</em><em> </em><em>m</em>

<u>We need to find time</u>

<h3>We know that ,</h3>

\begin{gathered} {\underline{\boxed{ \rm {\red{Speed \:  =  \:  \frac{Distance}{Time} }}}}}\end{gathered}

<h3>So ,</h3>

\begin{gathered} {\underline{\boxed{ \rm {\orange{Time \:  =  \:  \frac{Distance}{Speed} }}}}}\end{gathered}

<h3><u>Substuting</u><u> the</u><u> values</u></h3>

\begin{cases} \large\rm{\purple{ {\leadsto} }} \:  \: Time \:  =  \:  \frac{32}{8} \\  \\ \large\rm{\purple{ {\leadsto} }} \:  \: Time \:  =  \:   \cancel\frac{32}{8} \\  \\ \large\rm{\purple{ {\leadsto} }} \:  \: Time \:  =  \:  4 \: seconds \end{cases}

6 0
3 years ago
А<br> _ is a prediction about the outcome of a test or experiment.<br> Answer here<br> SUBM
Kamila [148]
Is his hypothesis if the have answer choices
4 0
3 years ago
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