Answer:
What is the power of focus from the eye when a subject looks from 20 to 500 from its eye?
Explanation:
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The Earth spins on its axis and also orbits around the Sun. For this problem use the following constants. Mass of the Earth: 5.97 × 10^24 kg (assume a uniform mass distribution) Radius of the Earth: 6371 km Distance of Earth from Sun: 149,600,000 km
(i)Calculate the rotational kinetic energy of the Earth due to rotation about its axis, in joules.
(ii)What is the rotational kinetic energy of the Earth due to its orbit around the Sun, in joules?
Answer:
(i) KE= 2.56e29 J
(ii) KE= 2.65e33 J
Explanation:
i) Treating the Earth as a solid sphere, its moment of inertia about its axis is
I = (2/5)mr² = (2/5) * 5.97e24kg * (6.371e6m)²
I = 9.69e37 kg·m²
About its axis,
ω = 2π rads/day * 1day/24h * 1h/3600s
ω= 7.27e-5 rad/s,
so its rotational kinetic energy
KE = ½Iω² = ½ * 9.69e37kg·m² * (7.27e-5rad/s)²
KE= 2.56e29 J
(ii) About the sun,
I = mR²
I= 5.97e24kg * (1.496e11m)²
I= 1.336e47 kg·m²
and the angular velocity
ω = 2π rad/yr * 1yr/365.25day * 1day/24h * 1h/3600s
ω= 1.99e-7 rad/s
so
KE = ½ * 1.336e47kg·m² * (1.99e-7rad/s)²
KE= 2.65e33 J
Answer:
128.9 N
Explanation:
The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:
where
F is the force
is the change in momentum
is the time interval
The change in momentum can be written as
where
m = 0.04593 kg is the mass of the ball
u = 0 is the initial velocity of the ball
is the final velocity of the ball
Substituting into the original equation, we find the force exerted on the golf ball:
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
The matter in gaseous state can be expanded to occupy the volumes of the container.
<h3>
Volume of each of the container</h3>
The volume of each of the container is calculated as follows;
<h3>Volume of the rectangular container</h3>
V = 5 in x 6 in x 3 in
V = 90 in³
<h3>Volume of the cylindrical container</h3>
V = πr²h
V = (π)(2.5 in)²(8 in)
V = 157.1 in³
<h3>Volume of the matter</h3>
Vm = 3 in x 4 in x 5 in
Vm = 60 in³
<h3>Matter in solid and liquid state</h3>
Matter has fixed volume in solid and liquid state.
In solid and liquid the matter can occupy the 90 in³ and 157.1 in³ volume.
<h3>Matter in gaseous state</h3>
Matter has no definite volume in gaseous state.
The matter in gaseous state can be expanded to occupy the volumes of the container.
Learn more about states of matter here:
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