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3 years ago

Which part of the manufacturing process involves heating and rolling blocks of steel into flat sheets and bars?

Physics

1 answer:

faltersainse [42]3 years ago

8 0

A. Forming

Explanation:

Metal forming is a metallurgical process which involves heating and rolling blocks of steel into flat sheets and bars.

Metal forming is the process of working metals and utilizing its properties to form different shapes.

Metal forming is made possible by metallic bonds in metals.
The bulk of the physical properties of metals can be attributed to these bond types.
In metal forming, metals are shaped into different substances.
Metal forming preserves the mass of the metallic body and the shapes modified by force.

Learn more:

Metals brainly.com/question/9053565

#learnwithBrainly

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Julli [10]

From equation of motion v^2 = u^2 +2aS

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2 years ago

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Which container most likely contains a liquid

vlabodo [156]

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3 years ago

Calculate the workdone to stretch an elastic string by 40cm if a force of 10 newton produces an extension of 4cm in it

notka56 [123]

Answer:

Workdone = 20 Joules

Explanation:

Given the following data;

Force = 10N

Extension, e = 4cm to meters = 4/100 = 0.04 meters

Workdone extension = 40cm to meters = 40/100 = 0.4 meters

To find the work done;

First of all, we would find the spring constant using the formula;

Force = spring constant * extension

10 = spring constant * 0.04

Spring constant = 10/0.04

Spring constant = 250 N/m

Next, we find the work done;

Workdone = ½ke²

Where;

k is the spring constant.

e is the extension.

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Workdone = ½ * 250 * 0.4²

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2 years ago

The diagram shows a car moving along a road.

crimeas [40]

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3 years ago

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A typical helicopter has four blades that rotate at 334 rpm and have a total kinetic energy of 4.55 105 J. What is the magnitude

djyliett [7]

Answer:

the magnitude of the total angular momentum of the blades is 743.71 kg·m²

Explanation:

Converting the angular speed into radians per second:

ω = 334 rpm · (2π rad / 1 rev) · (1 min / 60 s)

ω = 34.98 rad/s

The rotational kinetic energy of the blades is given by:

EK = 1/2 I ω²

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I is the moment of inertia
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Therefore, rearranging the above equation, we get:

1/2 I ω² = EK

I ω² = 2 EK

I = 2(EK) / ω²

I = 2(4.55 × 10⁵ J) / (34.98 rad/s)²

I = 743.71 kg·m²

Therefore, the magnitude of the total angular momentum of the blades is 743.71 kg·m².

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3 years ago