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3 years ago

13

How much heat is absorbed by a 450g gold block as energy from the sun causes its temperature to change from 27°C to 32°C? (Speci

fic heat capacity of gold is 0.47 cal/g°C) SHOW YOUR WORK *

1 answer:

kotegsom [21]3 years ago

5 0

Answer:

Q = 1057.5 [cal]

Explanation:

In order to solve this problem, we must use the following equation of thermal energy.

$Q=m*C_{p}*(T_{final}-T_{initial})$

where:

Q = heat energy [cal]

Cp = specific heat = 0.47 [cal/g*°C]

T_final = final temperature = 32 [°C]

T_initial = initial temperature = 27 [°C]

m = mass of the substance = 450 [g]

Now replacing:

$Q=450*0.47*(32-27)\\Q=1057.5[cal]$

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61. A physics student has a single-occupancy dorm room. The student has a small refrigerator that runs with a current of 3.00 A

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$percentage = 21.3$ %

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$percentage = 2.13 \times 10^{-5}$ %

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As we know that total power used in the room is given as

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$P = i^2 R$

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Part b)

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3 years ago