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just olya [345]
3 years ago
8

If you know the amplitude of a wave, you know the distance from

Physics
2 answers:
Elan Coil [88]3 years ago
7 0

Answer:

the equilibrium of one wave to the crest of the same wave.

Explanation:

The amplitude of a wave corresponds to the distance between the equilibrium position of the wave and the crest of the same wave (or the distance between the equilibrium position and the through of the same wave), therefore we see that this definition corresponds to option C,

the equilibrium of one wave to the crest of the same wave.

Leokris [45]3 years ago
5 0

Answer:

The equilibrium of one wave to the crest of the same wave

Explanation:

♥️

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A point on the string of a violin moves up and down in simple harmonic motion with an amplitude of 1.24 mm and frequency of 875
mario62 [17]

Using

V = Amplitude x angular frequency(omega)

But omega= 2πf

= 2πx875

=5498.5rad/s

So v= 1.25mm x 5498.5

= 6.82m/s

B. .Acceleration is omega² x radius= 104ms²

5 0
3 years ago
Read 2 more answers
1) The current in a light bulb is 0.335 Amps. How long does it take for a total charge of 2.76 C to
uysha [10]

Answer:

Time=8.23880597 seconds

Explanation:

Quantity of charge(q)=2.76c

Current(I)=0.335A

Time(t)=?

t=q/I

t=2.76/0.335

t=8.23880597seconds

7 0
3 years ago
10. In Freudian theory, which one of the following is an example of a Thanatos instinct, which includes aggression, trauma, and
Lelechka [254]
D substance abuse :) hope this helps
8 0
2 years ago
Calculate the binding energy per nucleon of the helium nucleus 52he. express your answer in millions of electron volts to four s
Vitek1552 [10]
The main formula is given by Eb/nucleon = Eb/ mass of nucleid
as for <span>52He, the mass is 5
so by applying Einstein's formula Eb=DmC², Eb=</span><span>binding energy
</span><span>52He-----------> 2 x 11p + 3 x10n is the equation bilan
</span>so Dm=2 mp + (5-2)mn-mnucleus, mp=mass of proton=1.67 10^-27 kg
                                                        mn=mass of neutron=<span>1.67 10^-27 kg
                                                        </span><span>m nucleus= 5
Dm= 2x</span>1.67 10^-27 kg+ 3x<span>1.67 10^-27 kg-5=  - 4.9 J
Eb= </span> - <span>4.9 J x c²= -4.9 x 9 .10^16= - 45 10^16 J
so the answer is Eb /nucleon = Eb/5= -9.10^16 J, but 1eV=1.6 . 10^-19 J
so </span><span>-9.10^16 J/ 1.6 10^-19=  -5.625 10^35 eV

the final answer is </span><span>Eb /nucleon </span><span>=  -5.625 x10^35 eV</span>
8 0
3 years ago
An electric immersion heater is put at the bottom of a large tank of water. The water next to the heater becomes warm
djyliett [7]

Answer:

when the water is heated with immersion heater, the water becomes less dense due to which the warm water rises up and the cooler water fills it's space.

4 0
2 years ago
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