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sergejj [24]
4 years ago
10

Can show some work for 4x = -12

Chemistry
2 answers:
timama [110]4 years ago
6 0
4x = -12

First, divide both sides by 4. / Your problem should look like: x =  -\frac{12}{4}
Second, since 4 goes into 3 to get 12, simplify it by 3. / Your problem should look like: x = -3

Answer: x = -3

Ksivusya [100]4 years ago
5 0
4x=-12
divide 4 on both sides 4x divided by 4 is x then u take 12 divided by 4 and it equals -3 so x= -3
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I need chemistry help! How would I set up these problems?
Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x 10^{11} m

Time taken = \frac{Distance}{Speed}

= \frac{1.5 x [tex] 10^{11} m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed = \frac{distance}{time}

= \frac{63360 inches}{535.2 s}

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x 10^{-2} m

Time taken = 8.92 min

Speed = \frac{distance}{time}

= \frac{63360 x 2.54 x [tex] 10^{-2} m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ \frac{1}{60 hour}

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

4 0
3 years ago
How many grams of hydrogen must react if the reaction needs to produce 31.75 grams of nh3
leva [86]
X= (3*2)(31.75)/(2*17)3*31.75/17
=5.603g H2

Answer: 5.603g H2

It’s all quite simple actually considering the fact the M(NH3) = 14 + 1*3 = 17g/mol
And M(H2) = 2*1 2g/mol

So 3H2 + N2 >> 2NH3

Givin that Xg is 31.75g

-HOPE THAT HELPED IN A WAY!!☺️
7 0
3 years ago
In a 200 cm3 container, a certain amount of O2 gas is held with a piston at equilibrium with the external pressure being 1 bar.
Maslowich

Answer:

a) V2 = 200.161 cm³

b)  Wexp = 0.0161 J done by the system

c) ΔU = 1.984 J

d) ΔH = 2.006 J

Explanation:

ΔU = Q + W.....first law

a) at constant temperature (298 K ):

∴ ΔU = 0 ⇒ Q = - W

∴ W = - ∫ P dV

⇒ Q = ∫ PdV

∴ PV = nRT

⇒ P = nRT / V

⇒  Q = ∫ nRT dV/V

⇒ Q = nRT Ln ( V2 / V1 )....assuming n O2 = 1 mol

⇒  Q / nRT = Ln ( V2 / V1 )

⇒ 2 J / (( 1mol) ( 8.314 J/molK * 298 K )) = Ln ( V2 / V1 )

⇒ 8.072 E-4 = Ln ( V2 / V1 )

⇒ 1.001 = V2 / V1

⇒ V2 = 1.001 * 200 cm³

⇒ V2 = 200.161 cm³  ( 2.00161 E-4 m³)

b) Wexp = - ∫ PdV.......work done by the system ( - )

P = 1 bar = 10197.2 Kgf/m²

⇒ W exp = - 10197.2 Kgf/m² * ( 2.00161 E-4 - 2.00 E-4 )m³

⇒ W exp = - 1.642 E-3 Kgf *m ( - 0.0161 J )

c) ΔU = Q + W

⇒ ΔU = 2 J - 0,0161 J

⇒ ΔU = 1.984 J   ( 0.202 Kgf*m )

d) H = U + PV.....ideal gas

⇒ ΔH = Δ ( U + PV )

⇒ ΔH = ΔU + P2V2 - P1V1

⇒ ΔH = 0.202  + (( 10197.2 * 2.00161 e-4 )) - (( 10197.2 * 2.00 E-4 ))

⇒ ΔH = 0.202 + 2.041 - 2.0394

⇒ ΔH = 0,204 Kgf*m ( 2.006 J )

8 0
4 years ago
What are the particles that are found in the nucleus of an atom
Alinara [238K]

Answer:

Protons and Neutrons

Explanation:

6 0
3 years ago
How many grams of aluminum chloride are produced when 6.73 g of aluminum react with an excess of chlorine gas?
sergejj [24]

Answer:

33.3 g AlCl3

Explanation:

First:

You need a balanced chem equation.

2Al + 3Cl2 --->2AlCl3

So now you use this to set up train track method which helps us cancel out the units. Also we dont care about chlorine because it is excess.

6.73g Al x 1mol Al/26.98g Al x 2mol AlCl3/2molAl x 133.34g AlCl3/1molAlCl3

= 33.3 g AlCl3

8 0
4 years ago
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