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NNADVOKAT [17]
3 years ago
6

When an atom combines chemically with another atom it either gains loses or shares?

Chemistry
1 answer:
Leokris [45]3 years ago
7 0
When an atom combines chemically with another atom, it either gains, loses, or shares ELECTRONS.
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A man ran 60.5 km, how far is this in yards?
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Answer:

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Although both N2 and 02 are naturally present in the air we breathe, high levels of NO and NO2 in the atmosphere occur mainly in
joja [24]

Answer:

(a) Increasing the temperature adds heat which is a reactant shifting the equilibrium rightwards.

(b) Pressure has no effect since the change in the number of moles is zero.

Explanation:

Hello,

In this case, one could represent the given reaction as:

N_2(g)+O_2(g)+ \Delta _rH \leftrightarrow 2NO

Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

Furthermore, for the (b) statement, since the change in the number of moles is zero, based on the stoichiometric coefficients as shown below:

\Delta \nu =2-1-1=0

Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:

Kp=Kc(RT)^{\Delta \nu }

Thus, since \Delta \nu =0, Kp=Kc, so no effect in concentration is due to the pressure.

Best regards.

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3 years ago
Modern atomic theory states that the atom is a diffuse cloud surrounding a small, dense nucleus. Identify which particle is in t
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4 0
3 years ago
The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm
Natali [406]

Answer: The actual free-energy change for the reaction  -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

  Fructose 1,6-bisphosphate \rightleftharpoons Glyceraldehyde 3-phosphate + DHAP

For the given reaction, \Delta G^{o} is 23.8 kJ/mol.

As we know that,

       \Delta G = \Delta G^{o} + RT ln Q

Here,    R = 8.314 J/mol K,       T = 37^{o} C

                                                    = (37 + 273) K

                                                    = 310.15 K

Fructose 1,6-bisphosphate = 1.4 \times 10^{-5} M

Glyceraldehyde 3-phosphate = 3 \times 10^{-6} M

DHAP = 1.6 \times 10^{-5} M

Expression for reaction quotient of this reaction is as follows.

    Reaction quotient = \frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}

        Q = \frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}

            = 3.428 \times 10^{-6}

Now, we will calculate the value of \Delta G as follows.

          \Delta G = \Delta G^{o} + RT ln Q

                      = 23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})

                      = -8647.73 J/mol

                      = -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction  -8.64 kJ/mol.

7 0
3 years ago
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