The answer is 200 J
The kinetic energy (KE) is:
KE = 1/2 m * v²
m - mass of the object
v - velocity of the object
We have:
m = 4 kg
v = 10 m/s
KE = 1/2 * 4 kg * 10² m/s
KE = 200 J
Answer:
8) 45 volt
9) 8 ohms
100 volt
Explanation:
using ohms law all through
8) v = 3×15
9) R= 120/15
the last V=100×1
Automobiles have they highest cost for of pollution in the air
The enthalpies of formation of each of the compound involved in the chemical reaction presented above are given below:
CO2: -393.5 kJ/mol
CO: -99 kJ/mol
O2: 0 kJ/mol
As observed O2 will not have enthalpy of formation as it is a pure substance.
To calculate for the enthalpy of reaction,
enthalpy of formation of products - enthalpy of formation of reactants
= (-99 kJ/mol) - (-393.5 kJ/mol)
= 294.5 kJ/mol
ANSWER: 294.5 kJ/mol
It is B nevermind I thought it was c but it wasn't.
