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kondaur [170]
3 years ago
11

Given a second class lever with a distance of 5.00 feet from the fulcrum to the effort and a distance of 33.0 inches from the re

sistance to the fulcrum, what is the maximum amount of weight that can be lifted with 25 lbs of effort.
A. 165 Lbs
B. 13.8lbs
C. 45.5lbs
D. 3.79lbs
Physics
1 answer:
leva [86]3 years ago
7 0

Answer:

The correct answer is C. 45.5 lbs.

Explanation:

In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.

The formula for any problem involving a lever is:

F_ed_e=F_ld_l

Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.

The parameter of the formula that you need is F_l:

F_l=\frac{F_ed_e}{d_l}

The conversion from feet to inches is 1 ft is equal to 12 inches. In this case, 5 ft are equal to 60 inches.

F_l=\frac{25*60}{33}

F_l=45.5 lbs

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3 years ago
In a research facility, a person lies on a horizontal platform which floats on a film of air. When the person's heart beats, it
anastassius [24]

Answer: 3.48g

Explanation:

here, we will be using conservation of momentum to solve the problem. i.e the total momentum remains unchanged, unless an external force acts on the system. We'll in thus question, there is no external force acting in the system.

Remember, momentum = mass * velocity, then

mass of blood * velocity of blood = combined mass of subject and pallet * velocity of subject and pallet

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7 0
3 years ago
Read 2 more answers
Which of the following is a conductor?<br><br> copper<br> water<br> aluminum<br> all of the above
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Answer:

D all of the above

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4 0
3 years ago
A plane passes over Point A with a velocity of 8000 m/s north. Forty seconds later it passes over Point B at a velocity of 10,00
Airida [17]

Answer:

The planes’ acceleration from A to B is 500m/s^2

Explanation:

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The acceleration is defined as the rate of change of velocity with time

we know that the expression for acceleration is given as

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3 years ago
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The maximum force of static friction is the product of normal force (P) and the coefficient of static friction (c). In a flat surface, normal force is equal to the weight (W) of the body. 
 
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Solving for the static friction force (F), 
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Therefore, the maximum force of static friction is 1.794 N. 



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3 years ago
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