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Sedbober [7]
3 years ago
9

A 3.0 kg block is pushed by a 14 N force. If µ = 0.6, will the block move?

Physics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

The block will not move.

Explanation:

We'll begin by calculating the frictional force. This can be obtained as follow:

Coefficient of friction (µ) = 0.6

Mass of block (m) = 3 Kg

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (R) = mg = 3 × 10 = 30 N

Frictional force (Fբ) =?

Fբ = µR

Fբ = 0.6 × 30

Fբ = 18 N

From the calculations made above, the frictional force of the block is 18 N. Since the frictional force (i.e 18 N) is bigger than the force applied (i.e 14 N), the block will not move.

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dem82 [27]

Answer:

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Explanation:

Given that,

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c=f\lambda

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f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.13\times 10^{-9}}\\\\f=2.30\times 10^{18}\ Hz

So, the frequency of an x-ray is 2.30\times 10^{18}\ Hz. Hence, this is the required solution.

5 0
3 years ago
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need Read this excerpt from "Not a Dove, But No Longer a Hawk."

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Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

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Thus, the GPE is:

U=W.h

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3 0
3 years ago
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marishachu [46]

Answer:

Explanation:

Given that,

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We know that, 1rev = 2πrad

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P = 942.48 Watts

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6 0
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