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3 years ago

PLEASE HELP I NEED THIS ANSWER BADLY!!!!!!!! Explain how might an animal respond to stimuli as compared to a plant?

Physics

1 answer:

Misha Larkins [42]3 years ago

5 0

Explanation:

Animas and plants react to stimuli which may come from other living things or from the environment. A stimulus causes the organism which receivs it to respond to it. Therefore the stimulus changes the behavior in the organism in some way.

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If a person can run 10 km in 2 hours, what is the person's speed? Include your work with your answer.

Pachacha [2.7K]

<span>Buddy, remember one formula.. speed=distance/time your all problems will be solved. in this case the answer is 5 km per hr</span>

4 0

3 years ago

Read 2 more answers

A certain airplane has a speed of 290.0 km/h and is diving at an angle of 0 : 30.0" below the horizontal when the pilot releases

prisoha [69]

Answer:

10.03 s is the time the decoy is in the air

Explanation:

From the information given we know:

$\theta_{0}=-30$ because is measured clockwise from horizontal.

The initial speed of the decoy is the plane's speed at the moment of release $v_{0}=290 \:\frac{km}{h}$

We will need to work in meters and m/s, so $290 \:\frac{km}{h} \cdot \frac{1000 \:m}{km} \cdot \frac{1\:h}{3600\:s} = 80.56 \:\frac{m}{s}$

The horizontal motion of a projectile is given by:

$x-x_{0}=v_{0x}\cdot t$

because $v_{0x}=v_0cos(\theta_{0})$ , this becomes

$x-x_{0}=(v_0cos(\theta_{0}))\cdot t$

We have that $\Delta x= 700\:m$ , solving for <em>t, </em>we have

$t=\frac{\Delta x}{v_{0}cos\theta_{0}} \\t=\frac{700 \:m}{(80.56 \:\frac{m}{s} )\cdot cos(-30)} \\t= 10.03 \:s$

5 0

3 years ago

A 300-N force acts on a 25-kg object. The acceleration of the object is ____.

andrey2020 [161]

12m/s^2 is the answer

7 0

3 years ago

Suppose an atom has a mass number of 23. What does this mean?

lawyer [7]

The number of protons in the nucleus dose not equal the number of neutrons.

6 0

3 years ago

Read 2 more answers

1. Two blocks travel along a level frictionless surface. Block A is initially moving to the right at 5.0 m/s, while block B is i

ad-work [718]

Answer: 2.67 m/s

Explanation:

Given

Mass of block A is $m_a=2\ kg$

mass of block B is $m_b=3\ kg$

The initial velocity of block A $u_a=5\ m/s$

the initial velocity of block B is $u_b=0$

After collision velocity of block A is $v_a=1\ m/s$

Conserving momentum

$m_au_a+m_bu_b=m_av_a+m_bv_b\\\\2\times 5+3\times0=2\times 1+3\times v_b\\\\v_b=\dfrac{8}{3}=2.67\ m/s$

The momentum of block A after the collision is $P_a=2\times 1=2\ kg.m/s$

Therefore, there is no change in sign.

6 0

3 years ago