Ask question

Ask question

All categories

3 years ago

7

During a lab experiment, a student took his resting pulse rate, counting 25 beats in 20 seconds. What was the student's pulse ra

te in beats per minutes (bpm)?

1 answer:

kkurt [141]3 years ago

8 0

Answer:

75 bpm

Explanation:

60 seconds in a minute

60seconds / 20 seconds = 3

25 beats * 3 = 75 bpm

You might be interested in

Pete is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his spe

Lubov Fominskaja [6]

8.33333333333333333333333333

3 0

4 years ago

If Joey ran 60 meters in 10 seconds, then his velocity is ________ m/s.

BabaBlast [244]

Answer:

6 m/s

Explanation:

6 0

4 years ago

Read 2 more answers

A bullet with a mass of 20 g and a speed of 960 m/s strikes a block of wood of mass 4.5 kg resting on a horizontal surface. The

Rufina [12.5K]

Answer:

<h2>4.25m/s</h2><h2>E. None of the option is correct</h2>

Explanation:

Using the law of conservation of momentum to solve the problem. According to the law, the sum of momentum of the bodies before collision is equal to the sum of the bodies after collision. The bodies move with the same velocity after collision.

Mathematically.

mu + MU = (m+M)v

m and M are the masses of the bullet and the block respectively

u and U are their respective velocities

v is their common velocity

from the question, the following parameters are given;

m = 20g = 0.02kg

u = 960m/s

M = 4.5kg

U =0m/s (block is at rest)

Substituting this values into the formula above to get v;

0.02(960)+4.5(0) = (0.02+4.5)v

19.2+0 = 4.52v

4.52v = 19.2

Dividing both sides by 4.52

4.52v/4.52 = 19.2/4.52

v = 4.25m/s

Since they have the same velocity after collision, then the speed of the block immediately after the collision is also 4.25m/s

4 0

4 years ago

The coefficent of static friction between the floor of a truck and a box resting on it is 0.38. The truck is traveling at 87.9 k

nekit [7.7K]

Answer:

$d=79.9m$

Explanation:

From the question we are told that:

coefficient of static friction $\mu=0.38$

Velocity $v=87.9=>24.41667m/s$

Generally the equation for Conservation of energy is mathematically given by

$\mu*mgd = 0.5 m v^2$

$d=\frac{0.5*24.42^2}{0.38*9.8}$

$d=79.9m$

3 0

3 years ago

A wagon weighs 1,800 N and is pulled by a horse at a speed of 0.40 meters/ second. What is the power of this horse

Alona [7]

Answer:

Power=720[watt]

Explanation:

We need to remember the definition of mechanical work which is equal to the product of the force applied by the distance traveled.

In this problem, we have to find the power which is defined as the work divided into the time in which such work is performed. This way if we have the displacement and the time, this will be the speed with which this work is done.

$Power= W/T\\T=time [s]\\W=work [J]\\Power = F*V\\where\\V=velocity [m/s]\\Power=1800 * 0.4 = 720 [watt]$

4 0

3 years ago

Read 2 more answers