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KonstantinChe [14]
3 years ago
15

6-What is the difference between the critical point and the triple point?

Engineering
2 answers:
hichkok12 [17]3 years ago
8 0

Answer:

The triple point represents the combination of pressure and temperature that facilitates all phases of matter at equilibrium. The critical point terminates the liquid/gas phase line .

Explanation:

Svetradugi [14.3K]3 years ago
8 0

Explanation:

<h2><u>Critical Point :</u></h2>
  • It's the end point of equilibrium curve .
  • It's typically higher than standard temperature.
  • pressure is also higher than standard pressure.

<h2><u>T</u><u>r</u><u>i</u><u>p</u><u>l</u><u>e</u><u> </u><u>Point</u><u> </u><u>:</u></h2>
  • It's point where the three equilibrium curves meet.
  • Temperature is lower than standard temperature.
  • pressure is lower than standard pressure.

<u>A</u><u>d</u><u>d</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u>a</u><u>l</u><u> </u><u>points</u><u> </u><u>:</u>

  • The triple point represents combination of pressure .
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The correct statement about the lift and drag on an object is:_______
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Answer:

(a). the resultant force in the direction of the freestream velocity is termed the drag and the resultant force normal to the freestream velocity is termed the lift

Explanation:

When a fluid flows around the surface of an object, it exerts a force on it. This force has two components, namely lift and drag.

The component of this force that is perpendicular (normal) to the freestream velocity is known as lift, while the component of this force that is parallel or in the direction of the fluid freestream flow is known as drag.

Lift is as a result of pressure differences, while drag results from forces due to pressure distributions over the object surface, and forces due to skin friction or viscous force.

Thus, drag results from the combination of pressure and viscous forces while lift results only from the<em> pressure differences</em> (not pressure forces as was used in option D).

The only correct option left is "A"

(a). the resultant force in the direction of the freestream velocity is termed the drag and the resultant force normal to the freestream velocity is termed the lift

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The heat required to raise the temperature of m (kg) of a liquid from T1 to T2 at constant pressure is Z T2CpT dT (1) In high sc
a_sh-v [17]

Answer:

(a)

<em>d</em>Q = m<em>d</em>q

<em>d</em>q = C_p<em>d</em>T

q = \int\limits^{T_2}_{T_1} {C_p} \, dT   = C_p (T₂ - T₁)

From the above equations, the underlying assumption is that  C_p remains constant with change in temperature.

(b)

Given;

V = 2L

T₁ = 300 K

Q₁ = 16.73 KJ    ,   Q₂ = 6.14 KJ

ΔT = 3.10 K       ,   ΔT₂ = 3.10 K  for calorimeter

Let C_{cal} be heat constant of calorimeter

Q₂ = C_{cal} ΔT

Heat absorbed by n-C₆H₁₄ = Q₁ - Q₂

Q₁ - Q₂ = m C_p ΔT

number of moles of n-C₆H₁₄, n = m/M

ρ = 650 kg/m³  at 300 K

M = 86.178 g/mol

m = ρv = 650 (2x10⁻³) = 1.3 kg

n = m/M => 1.3 / 0.086178 = 15.085 moles

Q₁ - Q₂ = m C_p' ΔT

C_p = (16.73 - 6.14) / (15.085 x 3.10)

C_p = 0.22646 KJ mol⁻¹ k⁻¹

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3 years ago
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