W²-5w+14
1 answer:
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Answer:
(a) ------(3). (b)------(1) (c)-----(5) (d)------(2) ------ (e) -----4
Note: Kindly find an attached copy of the diagram associated with the solution to the question below.
Sources: the diagram to this question was researched from Quizlet
Explanation:
Solution
(1) Part (a)a waveform has a high frequency components compared to another waveform. the corresponding frequency components should be high.
So for the wave form a the corresponding frequency spectrum is (3)
(2) For part (b), waveform has three harmonics, the corresponding frequency spectrum is (1)
(3) The time domain waveform plot (c) is a sine wave but there exists a dc component.
Thus x[0] ≠0
For (c) the corresponding frequency spectrum is (5)
(4) For part (d) the corresponding frequency spectrum is (2)
(5) A sine wave is made of a single frequency only and its spectrum is a single point
For (e) the corresponding frequency spectrum is (4)
Answer:
save space = 1.9626 Gibibits
Explanation:
given data
recording song time = 3 minute = 180 seconds
song per sample = 24 bits per sample
frequency = 96 kHz
surround sound system = 5.1
solution
first we get here required space for 24 bits at 96 kHz that is
required space = 24 × 96 × 10³ × 6 × 180
required space = 2.48832 × bits
as 1 Gib bit = bits
so required space = 2.48832 × bits ÷
bits
required space = 2.3174 Gibibits ...............1
and
space required to save record 16 bit at 44.1 kHz
space required = 16 × 44.1 × 10³ × 3 × 180
space required = 0.381024 × bits
space required = 0.381024 × bits ÷
bits
space required = 0.3548 Gibibits ...........2
so
we get here that save space in 16 bit at 44.1 kHz
save space = 2.3174 Gibibit - 0.3548 Gibibits
save space = 1.9626 Gibibits