Consider a flat plate that is 25 mm long, 30 mm wide, and 1 mm thick and a 50 mm long cylinder with the same volume as the plate
. Compare the heat transfer of the plate in parallel air flow to the heat transfer of the cylinder in cross flow under the same conditions. Both the plate and cylinder have a surface temperature of 80°C. The air is at 25°C with a velocity of 3 m/s. Note: Use the Churchill and Bernstein correlation to determine the Nusselt number for the cylinder case.
1 answer:
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Answer:
The molecular weight will be "28.12 g/mol".
Explanation:
The given values are:
Pressure,
P = 10 atm
=
=
Temperature,
T = 298 K
Mass,
m = 11.5 Kg
Volume,
V = 1000 r
=
R = 8.3145 J/mol K
Now,
By using the ideal gas law, we get
⇒
o,
⇒
By substituting the values, we get
As we know,
⇒
or,
⇒
Answer:
heat loss per 1-m length of this insulation is 4368.145 W
Explanation:
given data
inside radius r1 = 6 cm
outside radius r2 = 8 cm
thermal conductivity k = 0.5 W/m°C
inside temperature t1 = 430°C
outside temperature t2 = 30°C
to find out
Determine the heat loss per 1-m length of this insulation
solution
we know thermal resistance formula for cylinder that is express as
Rth = .................1
here r1 is inside radius and r2 is outside radius L is length and k is thermal conductivity
so
heat loss is change in temperature divide thermal resistance
Q =
Q =
Q = 4368.145 W
so heat loss per 1-m length of this insulation is 4368.145 W