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NNADVOKAT [17]
3 years ago
15

Given the atomic radius of neon, 0.69 å, and knowing that a sphere has a volume of 4πr3/3, calculate the fraction of space that

ne atoms occupy in a sample of neon at stp.
Chemistry
2 answers:
Ainat [17]3 years ago
8 0

Answer:

The volume of Neon would be 15290811,94 pm^3

Explanation:

In order to solve this we just have to calculate the volume that the neon will occupy, its radius is 0,69 A or 154 pm with this we just have to calculate with the next formula:Volume: \frac{4r^3\pi }{3} \\Volume: \frac{4(154^3pm*3,14 }{3}\\Volume: 15290811,94 pm^3

So the volume of Neon would be 15290811,94 pm^3

8090 [49]3 years ago
6 0

First, compute the volume of one atom by means of the spherical volume formula given: 4pi (.69) ^3/3. You should get 1.376 A^3. One angstrom (A) cubed is about 1 x 10^-27 liters. Multiply and get a atomic volume of 1.376 x 10^-27 L. That is the volume of only one atom. Multiply this volume by 6.02 x 10^23 (Avogadro s Number) to get the total volume of the atoms. You should get 8.284 x 10^-4 L. Now that we have our total volume for our atoms in liters, divide that number by volume of any ideal gas at STP, which is 22.4 L according to my text. You should get a final answer of 3.7 x 10^-5.

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What substance cannot be broken down by chemical change
ki77a [65]

Potassium is the simplest form of matter and therefore can not be broken down by chemical change.

5 0
3 years ago
calculate the mols of alt gas if the volume is 0.97 liters at a temperature of 12 C and the pressure is 152 Kpa’s
katrin2010 [14]

Answer:

0.062mol

Explanation:

Using ideal gas law as follows;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821Latm/molK)

T = temperature (K)

Based on the information provided;

P = 152 Kpa = 152/101 = 1.50atm

V = 0.97L

n = ?

T = 12°C = 12 + 273 = 285K

Using PV = nRT

n = PV/RT

n = (1.5 × 0.97) ÷ (0.0821 × 285)

n = 1.455 ÷ 23.39

n = 0.062mol

4 0
2 years ago
Hydrogen reacts with iodine to form hydrogen iodide: H2[g] + 12[g] = 2H1[g] The
ELEN [110]

Answer:

follow my instagram to help you with your school work in general

6 0
3 years ago
A 250 mL sample of gas is collected over water at 35°C and at a total pressure of 735 mm Hg. If the vapor pressure of water at 3
ELEN [110]

Answer:

The volume of the gas sample at standard pressure is <u>819.5ml</u>

Explanation:

Solution Given:

let volume be V and temperature be T and pressure be P.

V_1=250ml

V_2=?

P_{total}=735 mmhg

1 torr= 1 mmhg

42.2 torr=42.2 mmhg

so,

P_{water}=42.2mmhg

T_1=35°C=35+273=308 K

Now

firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.

P_{gas}=P_{total}-P_{water}

=735-42.2=692.8 mmhg

Now

By using combined gas law equation:

\frac{P_1*V_1}{T_1} =\frac{P_2*V_2}{T_2}

V_2=\frac{P_1*}{P_2}*\frac{T_2}{T_1} *V_1

V_2=\frac{P_gas}{P_2}*\frac{T_2}{T_1} *V_1

Here P_2 \:and\: T_2 are standard pressure and temperature respectively.

we have

P_2=750mmhg \:and\: T_2=273K

Substituting value, we get

V_2=\frac{692.8}{750}*\frac{273}{308} *250

V_2= 819.51 ml

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1 year ago
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