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nydimaria [60]
2 years ago
8

Which part(s) of the reaction 2 HD(g) ⇀↽ H2(g) + D2(g) will be favored by an increase in the total pressure (resulting in compre

ssion)?
Chemistry
1 answer:
Sergio [31]2 years ago
7 0

Answer:

Neither side is favored

Explanation:

In a reaction at equilibrium in which reactants and products are gases, pressure is a factor that produces a shift of the equilibrium position. When the pressure is increased, the equilibrium is shifted to the side of the reaction with a fewer moles. In this reaction:

2 HD(g) ⇀↽ H₂(g) + D₂(g)

There is the same number of moles on both sides:

reactants side: 2 moles HD

products side: 1 mol H₂ + 1 mol D₂ = 2 moles

Therefore, the equilibrium position will not change.

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