230,000. and that weird u
hope this helps
0.4 g/ml.............................
Answer:
1.) 0.1 M
2.) 0.2 M
3.) 1 M
4.) Solution #3 is the most concentrated because it has the highest molarity. This solution has the largest solute to solvent ratio. The more solvent there is, the lower the concentration and molarity.
Explanation:
To find the molarity, you need to (1) convert grams NaOH to moles (via molar mass from periodic table) and then (2) calculate the molarity (via the molarity equation). All of the answers should have 1 sig fig to match the given values.
Molar Mass (NaOH): 22.99 g/mol + 16.00 g/mol + 1.008 g/mol
Molar Mass (NaOH): 39.998 g/mol
4 grams NaOH 1 mole
---------------------- x ------------------ = 0.1 moles NaOH
39.998 g
1.)
Molarity = moles / volume (L)
Molarity = (0.1 moles) / (1 L)
Molarity = 0.1 M
2.)
Molarity = moles / volume (L)
Molarity = (0.1 moles) / (0.5 L)
Molarity = 0.2 M
3.)
Molarity = moles / volume (L)
Molarity = (0.1 moles) / (0.1 L)
Molarity = 1 M
<span>C. Their direction of motion is south and north. </span>
Answer:
The answer to your question is: C₃H₃O This is my answer.
Explanation:
Data
Sample = 1.3109 g
CxHyOz
CO₂ = 3.2007 g
H₂O = 1.3102 g
Empirical formula = ?
MW CO2 = 44 g
MW H2O = 18 g
For Carbon
44 g -------------------- 12 g
3.2007 g ------------ x
x = (3.2007 x 12) / 44
x = 0.8729 g of Carbon
12 g of C -------------- 1 mol
0.8729 g -------------- x
x = (0.8729 x 1) / 12
x = 0.0727 mol of Carbon
For Hydrogen
18 g ---------------------- 1 g
1.3102 g ------------------- x
x = (1.3102 x 1) / 18
x = 0.0727 g of Hydrogen
1 g ------------------------ 1 mol
0.0727g ---------------- x
x = (0.0727 x 1)/1
x = 0.0727 mol of Hydrogen
For oxygen
g of Oxygen = g of sample - g of Carbon - g of hydrogen
g of Oxygen = 1.3109 - 0.8709 - 0.0727
g of Oxygen = 0.3673
16 g of Oxygen ------------- 1 mol of O
0.3673 g --------------------- x
x = (0.3673 x 1)/ 16
x = 0.0230 mol of Oxygen
Divide by the lowest number of moles
Carbon 0.0727 / 0.023 = 3.1 ≈ 3
Hydrogen 0.0727 / 0.023 = 3.1 ≈ 3
Oxygen 0.0230 / 0.023 = 1
C₃H₃O
