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The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.
Molar mass of the unknown compound = 223.94 g/mol (given)
Mass of each element present in the unknown compound is determined as:
- Mass of carbon,
:

- Mass of hydrogen,
:

- Mass of chlorine,
:

Now, the number of each element in the unknown compound is determined by the formula:

- Number of moles of
:

- Number of moles of
:

- Number of moles of


Dividing each mole with the smallest number of mole, to determine the empirical formula:


Multiplying with 2 to convert the numbers in formula into a whole number:
So, the empirical formula is
.
Empirical mass = 
In order to determine the molecular formula:
n = 
n = 
So, the molecular formula is:

Answer: Raw data, perhaps.
Explanation: I'm not certain what the question is seeking for an answer, but I would suggest "raw data" would be a reasonable choice. It reflects the data was recorded, but not yet processed to provide a conclusion or observation.
If one were a bit snarky, other possiblities include
- a pile of dung
- my labmate's scrawls, or
- the best web results I could find
The poles are located at the 90 degrees. The poles are extremely cold environments. If you think about how relatively close to the pole 60 degrees would be, you can assume it would be cold but not as extreme. So short summer, cold winters seems to be the most accurate.
You can also see in a map (attached) where the 60 degrees parallel actually is, and you can see what the climate tends to be in those areas.
What your going to do is take away the lowest number form the highest and subtract. Thats your answer...