Ni solution could be used to remove lead from lead (II) nitrate.
Explanation:
The removal of lead from lead nitrate will take place by displacement reaction.
In displacement reaction less reactive element is displaced by more reactive element form it compound.
The reactivity is decided by the placement of metal in the activity series.
A metal which is at higher position in the activity series will be able to displace the metal or element having lower position.
From the options given we will check their position in the activity series in comparison to Pb
Cu is lower in series than Pb hence cannot displace.
Hg is placed lower in the series than Pb hence cannot displace Pb.
Ag is placed lower than Pb in the series hence cannot displace Pb.
Ni is placed above the Pb in activity series hence can displace lead.
4 atoms of Oxygen are required to make 2 atoms of hydrogen. The compound H2O is 1 Hydrogen and 2 Oxygen.
For the answer to the question above, <span>1.18 x 3 = 3.55.</span>
<span>First, you need to find the ratio of F to F in each compound. It is the law of multiple proportions stating that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers. In this case, F would be the "one element" and S would be the "fixed mass", the ratio of F6 to Fx = 3:1 </span>
<span>therefore x would be 2 since there is less F in SFx and the ratio is 3:1. divide 6 by 3 and you get 2.</span>
The answer should be (4) they are negative subatomic particles and are found surrounding the nucleus. The nucleus is formed by neutrons and protons. Neutrons are neutral and protons are positive.
Answer:
K2CrO4
Explanation:
To find the empirical formula, we need to divide each element by its atomic mass. The atomic masses of potassium, chromium and oxygen are 39.0983, 51.9961 and 15.999 respectively. We make the divisions as follows:
K = 1.04/39.0983 = 0.027
Cr = 0.70/51.9961 = 0.013
O = 0.86/15.999 = 0.054
We now divide by the smallest which is the number of moles of the Chromium
K = 0.027/0.013 = 2
Cr = 0.013/0.013 = 1
K = 0.054/0.013 = 4 approximately
The empirical formula is thus:
K2CrO4
