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3 years ago

What is rectilinear propagation of light ?

Physics

2 answers:

Brut [27]3 years ago

7 0

Answer:

light travels in straight line

yuradex [85]3 years ago

6 0

Rectilinear propagation of light is the property of light due to which it travels in a straight line.

Foe example; Torch light

Hope it helps!

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Steam enters a well-insulated nozzle at 200 lbf/in.2 , 500F, with a velocity of 200 ft/s and exits at 60 lbf/in.2 with a velocit

Ede4ka [16]

Answer:

$386.2^{\circ}F$

Explanation:

We are given that

$P_1=200lbf/in^2$

$P_2=60lbf/in^2$

$v_1=200ft/s$

$v_2=1700ft/s$

$T_1=500^{\circ}F$

$Q=0$

$C_p=1BTU/lb^{\circ}F$

We have to find the exit temperature.

By steady energy flow equation

$h_1+v^2_1+Q=h_2+v^2_2$

$C_pT_1+\frac{P^2_1}{25037}+Q=C_pT_2+\frac{P^2_2}{25037}$

$1BTU/lb=25037ft^2/s^2$

Substitute the values

$1\times 500+\frac{(200)^2}{25037}+0=1\times T_2+\frac{(1700)^2}{25037}$

$500+1.598=T_2+115.4$

$T_2=500+1.598-115.4$

$T_2=386.2^{\circ}F$

7 0

4 years ago

All of the following are sources of calories except HELP ASAP!!!

sweet-ann [11.9K]

Answer:

vitamins don't contain calories

8 0

3 years ago

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the product of the pressure and the volume

11111nata11111 [884]

I’m stuck on this too

4 0

3 years ago

A rock is thrown straight downward from a tree limb with an initial velocity v0. The rock has constant downward acceleration of

viktelen [127]

Answer:

v₀ = 15 m/s

Explanation:

given,

initial velocity = v₀

down acceleration of rock = 10 m/s²

rock distance

S₄ = 7 x S₁

From kinematic equations

S = v₀ t+0.5 at²

at t = 1 s

S₁ = v₀ (1)+0.5 x 10 x 1²

S₁ = v₀+ 5......(1)

at t = 4 s

S₄ = v₀ (4)+0.5 x 10 x 4²

S₄ = 4 v₀+80.....(2)

from equation (1) and (2)

7( v₀ + 5 ) = 4 v₀ +80

3 v₀ = 80 - 35

3 v₀ = 45

v₀ = 15 m/s

3 0

4 years ago

A charge of 0.20uC is 30cm from a point charge of 3.0uC in vacuum. what work is required to bring the 0.2uC charge 18cm closer t

vlada-n [284]

Answer:

The correct answer is " $4.49\times 10^{10} \ joules$ ".

Explanation:

According to the question,

The work will be:

⇒ $Work=-\frac{kQq}{R}$

$=-\frac{1}{4 \pi \varepsilon \times (18-30)\times 3\times 0.2}$

$=-\frac{1}{4 \pi \varepsilon \times (-12)\times 3\times 0.2}$

$=\frac{0.3978}{\varepsilon }$

$=4.49\times 10^{10} \ joules$

Thus the above is the correct answer.

3 0

3 years ago

What is rectilinear propagation of light ?​

What is rectilinear propagation of light ?