Answer:
0.0097 mol·L⁻¹
Explanation:
The balanced equation is
2NOCl ⇌ 2NO₂ + Cl₂
Data:
Your value of Kc is incorrect. It should be
Kc =1.6 × 10⁻⁵
[NOCl] = 0.50 mol·L⁻¹
[NO] = 0.00 mol·L⁻¹
[Cl₂] = 0.00 mol·L⁻¹
Calculations:
1. Set up an ICE table.
2. Calculate the equilibrium concentrations
This is a cubic equation. Some calculators can solve cubic equations, but we can solve it by the method of successive approximations.
We will make changes to the right-hand side until the calculated value of x no longer changes,
(a) 1st approximation
Assume that 2x is negligible compared to 0.50. Then
(b) 2nd approximation
Assume that x= 0.010. Then
(b) 3rd approximation
Assume that x= 0.0097. Then
No change, so x = 0.0097.
[Cl₂] = x mol·L⁻¹ = 0.0097 mol·L⁻¹
Check:
It checks.
No of moles of Carbon, C = mass/ molar mass.
Molar mass of carbon = 12.0107. We only have to calculate the no of moles
of carbon to obtain carbon's mass. .
From Sucrose chemical formula C12H22O11 we know that there are 12
carbon atoms.
So there are 1.4x10^(20) x12 = 16.8 x 10^20 carbon atoms.
We will use avogardo's number to find out the number of carbon molecules
in the compound.
From Avogadro's no. One mole of any substance equals to 6.022140857
atoms.
So X mole contains 16.8 * 10^(20) carbon atom
(16.8x10^20 carbon atoms)/6.022 x10^23 particles/mol = 0.00279 mols
The molar mass of carbon is 12.0107g/mol so we'll multiply to get the mass:
0.00279 mols x 12 = 0.03348.
Answer:
Explanation:
The atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons. Since the boundary is not a well-defined physical entity, there are various non-equivalent definitions of atomic radius. Three widely used definitions of atomic radius are: Van der Waals radius, ionic radius, and covalent radius.
There are fewer oxygen atoms in the equation than hydrogen or carbon. Only the oxygen needs to be balanced. There are equal numbers of hydrogen and carbon.